Answer:
The number of tickets is increasing by 97% each year
Step-by-step explanation:
The question, which pertains to algebra, is asking for the solution to three equations involving three numbers. To solve the problem, we set up equations based on the information provided and then solve for the three unknowns. The solution is 10, 24, and 14.
This problem can be addressed using algebraic equations. We are given three unknown numbers a, b, and c. The problem provides us with the following information:
Using these equations, we can solve for a, b, and c. Our steps are:
So, the three numbers are 10, 24, and 14.
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The discriminant is 0. As the discriminant is 0 it will have equal roots.
And the real root is -2/3.
What is a Quadratic Equation?
In algebra, a quadratic equation is any equation that can be rearranged in a standard form where x represents an unknown, and a, b, and c represent known numbers, where a ≠ zero.
Conclusion: If a = zero, then the equation is linear, no longer quadratic, as there's no ax^2 term.
9+12x+4=0
a = 9 ; b = 12; c = 4;
discriminant = Δ = - 4ac
Δ = - (4*9*4) = 144 - 144 = 0
roots of quadratic equations are [ (-b ± √Δ)/ 2a)]
let roots of eqation are x1 & x2
As discriminant is zero so, x1=x2
x1 = x2 = -b/2a = - 12/(2*9) = -2/3
learn more about quadratic equations here brainly.com/question/1214333
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Answer:
hello :
9x^2+12x+4=0
a = 9 b = 12 c = 4
the discriminant Δ = b² - 4ac = 12² - 4(9) (4 ) =144 - 144 = 0
x1 = x2 = - b/2a = -12/18 = - 2/3
the real root is : - 2/3
Answer: on Edge its choice D or 2(x - 1/2)^2 - 27/2
Step-by-step explanation:
The other guy has the same answer just in decimal form and I'm a big brain boy so I helped out