MATHEMATICS HIGH SCHOOL

Given the equation 5x + y = 7, which equation below would cause a consistent-independent system? a.10x+2y=14 b.-15x-3y=-6 c.5x+y=-7 d.6x+2y=7

Answers

Answer 1

Answer: I did the test.
The answer is D. 6x + 2y = 7

Answer 2

Answer:

Answer:

the answer is D.

Step-by-step explanation:

Related Questions

Which sequence of transformations carries ABCD onto HGFE
The rational and the irrational numbers together are called whole numbers. true or false
24x + 34p = p Solve for p
The function p(x)=x(x-5)(x-2)(x+3) has four zeros. What is the smallest
From 19801980 to 20002000, the annual profit of a company was determined by subtracting from \$625{,}000$625,000 the product of \$25{,}000$25,000 and the number of years either before or after 19901990. Which of the following equations below could be used to determine in which year, xx, the profit was \$550{,}000$550,000?a.550−25∣x−1990∣=625b.625 - 25 | x - 1990 | = 550625−25∣x−1990∣=550c.625 +25 | x - 1990 | = 550625+25∣x−1990∣=550d.625 +25 | x + 1990 | = 550625+25∣x+1990∣=550

A field goal kicker lines up to kick a 44 yard (40m) field goal. He kicks it with an initial velocity of 22m/s at an angle of 55∘. The field goal posts are 3 meters high.Does he make the field goal?What is the ball's velocity and direction of motion just as it reaches the field goal post

Answers

Answer:

The ball makes the field goal.

The magnitude of the velocity of the ball is approximately 18.166 meters per second.

The direction of motion is -45.999º or 314.001º.

Step-by-step explanation:

According to the statement of the problem, we notice that ball experiments a parabolic motion, which is a combination of horizontal motion at constant velocity and vertical uniform accelerated motion, whose equations of motion are described below:

$x = x_(o)+v_(o)\cdot t\cdot \cos \theta$ (Eq. 1)

$y = y_(o) + v_(o)\cdot t \cdot \sin \theta +(1)/(2)\cdot g\cdot t^(2)$ (Eq. 2)

Where:

$x_(o)$ , $y_(o)$ - Coordinates of the initial position of the ball, measured in meters.

$x$ , $y$ - Coordinates of the final position of the ball, measured in meters.

$\theta$ - Angle of elevation, measured in sexagesimal degrees.

$v_(o)$ - Initial speed of the ball, measured in meters per square second.

$t$ - Time, measured in seconds.

If we know that $x_(o) = 0\,m$ , $y_(o) = 0\,m$ , $v_(o) = 22\,(m)/(s)$ , $\theta = 55^(\circ)$ , $g = -9.807\,(m)/(s)$ and $x = 40\,m$ , the following system of equations is constructed:

$40 = 12.618\cdot t$ (Eq. 1b)

$y = 18.021\cdot t -4.904\cdot t^(2)$ (Eq. 2b)

From (Eq. 1b):

$t = 3.170\,s$

And from (Eq. 2b):

$y = 7.847\,m$

Therefore, the ball makes the field goal.

In addition, we can calculate the components of the velocity of the ball when it reaches the field goal post by means of these kinematic equations:

$v_(x) = v_(o)\cdot \cos \theta$ (Eq. 3)

$v_(y) = v_(o)\cdot \cos \theta + g\cdot t$ (Eq. 4)

Where:

$v_(x)$ - Final horizontal velocity, measured in meters per second.

$v_(y)$ - Final vertical velocity, measured in meters per second.

If we know that $v_(o) = 22\,(m)/(s)$ , $\theta = 55^(\circ)$ , $g = -9.807\,(m)/(s)$ and $t = 3.170\,s$ , then the values of the velocity components are:

$v_(x) = \left(22\,(m)/(s) \right)\cdot \cos 55^(\circ)$

$v_(x) = 12.619\,(m)/(s)$

$v_(y) = \left(22\,(m)/(s) \right)\cdot \sin 55^(\circ) +\left(-9.807\,(m)/(s^(2)) \right)\cdot (3.170\,s)$

$v_(y) = -13.067\,(m)/(s)$

The magnitude of the final velocity of the ball is determined by Pythagorean Theorem:

$v =\sqrt{v_(x)^(2)+v_(y)^(2)}$ (Eq. 5)

Where $v$ is the magnitude of the final velocity of the ball.

If we know that $v_(x) = 12.619\,(m)/(s)$ and $v_(y) = -13.067\,(m)/(s)$ , then:

$v = \sqrt{\left(12.619\,(m)/(s) \right)^(2)+\left(-13.067\,(m)/(s)\right)^(2) }$

$v \approx 18.166\,(m)/(s)$

The magnitude of the velocity of the ball is approximately 18.166 meters per second.

The direction of the final velocity is given by this trigonometrical relation:

$\theta = \tan^(-1)\left((v_(y))/(v_(x)) \right)$ (Eq. 6)

Where $\theta$ is the angle of the final velocity, measured in sexagesimal degrees.

If we know that $v_(x) = 12.619\,(m)/(s)$ and $v_(y) = -13.067\,(m)/(s)$ , the direction of the ball is:

$\theta = \tan^(-1)\left((-13.067\,(m)/(s) )/(12.619\,(m)/(s) ) \right)$

$\theta = -45.999^(\circ) = 314.001^(\circ)$

The direction of motion is -45.999º or 314.001º.

The ball makes the field goal.

The magnitude of the velocity of the ball is approximately 18.166 meters per second.

The direction of motion is -45.999º or 314.001º.

According to the statement of the problem, we notice that ball experiments a parabolic motion, which is a combination of horizontal motion at constant velocity and vertical uniform accelerated motion, whose equations of motion are described below:

X=Xo+Vo*t*cosФ (Eq. 1)

Y=Yo+Vo*t*sinФ +(1/2)*g*t²(Eq. 2)

Where:

Xo,Yo - Coordinates of the initial position of the ball, measured in meters.

X,Y - Coordinates of the final position of the ball, measured in meters.

Ф- Angle of elevation, measured in sexagesimal degrees.

Vo - Initial speed of the ball, measured in meters per square second.

t - Time, measured in seconds.

If we know that Xo = 0m, Yo = 0m, Vo = 22m/s, Ф = 55°,g = -9.807m/s and X = 40m, the following system of equations is constructed:

40 = 12.618*t (Eq. 1b)

Y = 18.021*t-4.904*t² (Eq. 2b)

From (Eq. 1b):

t = 3.170s

And from (Eq. 2b):

Y = 7.847m

Therefore, the ball makes the field goal.

In addition, we can calculate the components of the velocity of the ball when it reaches the field goal post by means of these kinematic equations:

Vx = Vo*cosФ (Eq. 3)

Vy = Vo*cosФ+g*t (Eq. 4)

Where:

Vx - Final horizontal velocity, measured in meters per second.

Vy- Final vertical velocity, measured in meters per second.

If we know that Vo = 22m/s, Ф= 55°, g = -9.807m/s and t = 3.170s, then the values of the velocity components are:

Vx = (22m/s)*cos55°

Vx = 12.619m/s

Vy = (22m/s)*sin55°+(-9.807m/s²)*3.170s

Vy = -13.067m/s

The magnitude of the final velocity of the ball is determined by Pythagorean Theorem:

V = √(Vx²+Vy²) (Eq. 5)

Where is the magnitude of the final velocity of the ball.

If we know that Vx = 12.619m/s and Vy = -13.067m/s, then:

V = √((12.619m/s)²+(-13.067m/s)²)

V ≈ 18.166m/s

The magnitude of the velocity of the ball is approximately 18.166 meters per second.

The direction of the final velocity is given by this trigonometrical relation: Ф = tan^(-1)(Vy/Vx)(Eq. 6)

Where Ф is the angle of the final velocity, measured in sexagesimal degrees.

If we know that Vx = 12.619m/s and Vy = -13.067m/s, the direction of the ball is:

Ф = tan^(-1)((-13.067m/s)/(12.619m/s))

Ф = -45.999° = 314.001°

The direction of motion is -45.999º or 314.001º.

For more questions on magnitude.

brainly.com/question/32653785

#SPJ3

A function is graphed on a coordinate grid. As the domain values approach infinity, the range values approach infinity. As the domain values approach negative infinity, the range values approach negative infinity. To which family of functions might the described function belong?absolute value
exponential
cube root
square root

Answers

The family of functions to which the described function belongs is the C. Cube root.

What is a Cube Root?

This refers to the function family that contains a range that goes from the negative infinity to infinity.

Hence, we can see that from the given explanation of the function that the domain values approach infinity and the range values approach infinity, there is a similar shift to negative infinity and they belong to the cube root family.

Answers

There are 15 ways to choose 2 of the kittens from the litter

How to determine the number of ways?

The given parameters are:

Litter = 6
To select = 2

The number of ways to select the 2 kittens is:

Ways = $^nC_r$

This gives

Ways = $^6C_2$

The combination formula is:

$^nC_r = (n!)/((n - r)!r!)$

So, we have:

$^6C_2 = (6!)/((6 - 2)!2!)$

Evaluate the difference

$^6C_2 = (6!)/(4!2!)$

Expand

$^6C_2 = (6 * 5 * 4!)/(4! * 2 * 1)$

Evaluate the quotient

$^6C_2 = 15$

So, we have:

Ways = 15

Hence, there are 15 ways to choose 2 of the kittens from the litter

Answers

To find a percentage of a number, multiply the number by the decimal version of the percent.

For 94.12%, the decimal form is 0.9412 (because 94.12% really means 94.12 out of 100).

So, to find 94.12% of 2125, multiply the decimal form by the number:

2125 × 0.9412 =2000.05, so 2000 people finished the race.

Express the product of 4-3i and 2+i in simplest a+bi form

Answers

(4-3i)(2+i)=8+4i-6i-3i^2=8-2i+3=11-2i
recall that i*i= -1

Answer:

11-2i

Step-by-step explanation:

Pls pls help me bro i’m abt to fail

Answers

10 hours babysitting and 3 tutoring

Other Questions

I answered 5 questions that are EASY AS FUDGE LOL and i just want someones feedback to see if it is right WILL GIVE BRAINLIEST HELPPPPPPPPPPPPP at least take a look at it!1. The number of people that belong to a certain social website is 412 and growing at a rate of 5% every month.How many members will there be in 9 months?Enter your answer, rounded to the nearest whole number, in the box.MY ANSWER IS: 639......RIGHT OR WRONG2. The expression 15.85(1+x) gives the total cost of a toy, where x is the sales tax written in decimal form.What does 1 + x represent in the expression? percent of original price being paid in tax cost of toy percent of tax amount of tax 3. A population of lizards decreases exponentially at a rate of 12.5% per year.What is the equivalent monthly rate to the nearest hundredth of a percent? 0.20% 1.04% 1.11% 1.23%4. Enrollment was increasing at a rate of 20% per year.What was the monthly growth rate?Enter your answer, rounded to the nearest tenth of a percent, in the box.MY ANSWER IS: 1.7%5. The value of a truck after t years is represented by the function f(t)=22,200(0.92)t .What does the value 22,200 represent in this situation? The value of the truck increases by $22,200 each year. The initial value of the truck is $22,200. The value of the truck decreases by $22,200 each year. The value of the truck after t years is $22,200.

What does y =. I don’t know how to solve the domain

What’s the right answer?

Calculate the average speed of a gazelle that runs 140 meters in 5.0 seconds.