MATHEMATICS HIGH SCHOOL

The function p(x)=x(x-5)(x-2)(x+3) has four zeros. What is the smallest

Answers

Answer 1

Answer:

Answer: The smallest zero is -3.

Step-by-step explanation:

Zeros of a function are the values of input for which the function gives 0 output.

Here, the given function is,

p(x) = x(x-5)(x-2)(x+3)

For finding the zeroes of p(x),

p(x) = 0

⇒ x(x-5)(x-2)(x+3) = 0,

⇒ x = 0 or x - 5 = 0 or x-2=0 or x+3=0

⇒ x = 0 or x = 5 or x = 2 or x = -3

Thus, the zeros of the given function are 0, 5, 2, -3

In which -3 is smallest.

Answer 2

Answer: you can get the zeros by equating each factor by zero
so we have 0 , 5 , 2 , -3
so the smallest one is (-3)

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Answers

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The length of a rectangle is 3n+ 2 and its width is n-1. The perimeter of the rectangle is twice the sum of its length and its width. write an expression that represents the perimeter of the rectangle. Find the perimeter of the rectangle when n= 4 inches

Answers

Length, L = 3n + 2
Width, W = n - 1

Perimeter, P = 2*(L + W)

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