B) The momentum before the collision is greater than the momentum after the collision.
C) The momentum before the collision is less than the momentum after the collision.
The car A has a mass of 1200 kg.
The car B has the mass of 1900 kg.
It is given that velocity of car A is given as 22 Km/hr
The car B has the velocity of 25 Km/hr.
Let the mass of two bodies are denoted as
Let the velocity of cars A and B are denoted as
The momentum before collision is-
[Here p stand for momentum.]
We are asked to calculate the final momentum of the system after collision.
The answer of the question is based law of conservation of linear momentum.
As per law of conservation of linear momentum the sum total linear momentum for an isolated system is always constant.Hence irrespective of the type of collision[elastic and inelastic],the momentum of the system is always constant which is a universal truth.
Let after the collision the velocity of A and B are
Hence the final momentum of the system is-
As per the law of conservation of linear momentum, the initial and final momentum must be equal i.e
Hence the option A is right.
Answer:
The work done to the block
See
Workdone is Force×Displacement .
Also work done is total mechanical energy of body
Mechanical energy=Kinetic energy
So option C is correct
A neutron is absorbed by the original uranium-235 nucleus before it splits into two new nuclei, krypton-92 and barium-141, which also releases three additional neutrons. These three neutrons can then split three more uranium-235 nuclei, releasing more neutrons with each fission, and so on.
A U-235 nucleus splits into two pieces when it takes in an extra neutron. Fission is the name of this process. Two to three neutrons are released each time a U-235 nucleus splits. Consequently, starting a chain reaction is a possibility.
U-235 atoms take in free neutrons during fission. Due to this, U-235 becomes unstable and fragments into two light atoms known as fission products.
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