graph of exponential function going down from left to right in quadrant 1 through the point 0, 40 and approaching the x axis
graph of function f of x equals 50 multiplied by 0.82 to the power of x
graph of exponential function going down from left to right in quadrant 1 through the point 0, 4 and approaching the x axis
Answer:going down from left to right in quadrant 1 through the point 0, 40 and approaching the x axis
The domain of f o g is all x-values less than or equal to 1/4. So, the correct answer is B. 1.
What is Function ?
Function can be defined in which it relates an input to output.
To determine the domain of f o g, we need to first find the composition of f and g.
f o g(x) = f(g(x))
= √4(1/x - 4) = √(4/x - 16)
The domain of f o g is the set of all x-values for which the expression √(4/x - 16) is defined.
For the expression under the square root to be defined, we need:
4/x - 16 ≥ 0
4/x ≥ 16
x ≤ 4/16
x ≤ 1/4
Therefore, the domain of f o g is all x-values less than or equal to 1/4. So, the correct answer is B. 1.
To learn more about Function from given link.
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helppppppppppppppppp
p = 9 becsude 9 x 9 = 81 so yeah
Answer:
24 and 30
Step-by-step explanation:
The sum of two numbers is 54. Let's use the variables x and y to represent theses numbers:
x + y = 54
The smaller number is 6 less than the bigger one. Let's say that x is the smaller number and y is the bigger number:
y - 6 = x
Now we know that x is equivalent to y - 6. So, let's replace x with y - 6 in the original equation:
x + y = 54
y - 6 + y = 54
Combine like terms:
2y - 6 = 54
Now we can solve for y:
2y - 6 = 54
Add 6 to both sides of the equation to isolate the 2y:
2y = 60
Divide both sides by 2 to find the value of y:
y = 30
Now that we know the value of y, we can solve for x:
y - 6 = x
30 - 6 = x
24 = x
The value of the two numbers is 24 and 30.
Answer:
Draw 20 equilateral triangles such that 5 triangles having sides measure 4 cm , 7 triangles have sides measure 7 cm , 3 triangles have side 10 cm and rest of the triangles have side of measure 5 cm.
This will become a set of equilateral triangles .
Let consider a subgroup set of the original set of having equilateral triangle with side-length of 5 cm.
Then the number of triangle having side-length 5 cm= 20-5-7-3=5
Now, the fraction of the group having triangle with side- length 5 cm is given by:-