Hank: The y-intercept of a linear function is the same as the first term of an arithmetic sequence.
Hank's reasoning is being questioned for assuming that all sequences start with 1 and that the y-intercept of a linear function is always at x=0.
Given that,
Hank's reasoning is being discussed.
The claim is that Hank's reasoning is incorrect.
The reasoning involves sequences that begin with the term number 1, where x=1.
By convention,
The first term of a sequence starts with n = 1 instead of n = 0.
This is so n = 1 matches with 1st,
n = 2 matches with 2nd, and so on.
In contrast,
The y-intercept always occurs when x = 0.
So y = 3x+5 has a y-intercept of 5 when you plug in x = 0.
An arithmetic sequence:
f(n) = 2n+7 has its first term when n = 1.
So, the first term would be f(1) = 2(1)+7=9 instead of 7 as Hank claims.
To learn more about a function visit:
#SPJ3
The complete question is:
Hank's reasoning is incorrect because all sequences begin with the term number 1, which translates to x=1.
The y-intercept of a linear function is when x=0.
By convention, the first term of a sequence starts with n = 1 instead of n = 0. This is so n = 1 matches with 1st, n = 2 matches with 2nd, and so on.
In contrast, the y intercept always occurs when x = 0. So something like y = 3x+5 has a y intercept of 5 when you plug in x = 0.
An arithmetic sequence like f(n) = 2n+7 has its first term when n = 1. So the first term would be f(1) = 2(1)+7 = 9 instead of 7 as Hank claims.
Answer:
-3.7, -1.9, -1/2, 1 1/3, 1.6, 2 1/3
Step-by-step explanation:
I believe this is correct, if not feel free to let me know and I will fix it. I'm sorry in advance if this answer is wrong.
Answer:
-3.7, -1.9, -1/2, 1 1/3, 1.6, 2 1/3
Step-by-step explanation:
hope this helps! have a great day!