MATHEMATICS HIGH SCHOOL

Which fractions are equivalent to -30/48 ?A.
-5/8

B.
-15/24

C.
10/-16

D.
− 35 over 65 star times

Answers

Answer 1

Answer:

The answer is D

Because

-35/65 = -0.53

I hope that's help:)

Related Questions

.16 with the 6 repeating to a fraction
Round 0.5809 to the nearest hundred
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and there is a local min at x=-1 and an inflection point at x=-2. Find the values of a and b
Choose another correct name for the angle marked L6

Write a solution in Interval Notation - (you don't have to help me on all, 1 or 2 is fine c: )1) | m | -2 > 0

2) | x - 4 | - 3 > 5

3) | 6 + 9x | ≤ 24

4) | 1 - 5a | > 29

Answers

QUESTION 1

The given inequality is

$|m|-2>0$

We group like terms to get,

$|m|>2$

This implies that,

$-m>2$ or $m>2$ .

We simplify the inequality to get,

$m<-2$ or $m>2$ .

We can write this interval notation to get,

$(-\infty,-2)\cup (2,+\infty)$ .

QUESTION 2

$|x-4|-3\:>\:5$ .

We group like terms to get,

$|x-4|\:>\:5+3$ .

$|x-4|\:>\:8$

We split the absolute value sign to get,

$-(x-4)\:>\:8$ or $x-4\:>\:8$

This implies that,

$x-4\:<\:-8$ or $x-4\:>\:8$

$x\:<\:-8+4$ or $x\:>\:8+4$

$x\:<\:-4$ or $x\:>\:12$

We can write this interval notation to get,

$(-\infty,-4)\cup (12,+\infty)$ .

QUESTION 3

The given inequality is

$|6+9x|\leq 24$

We split the absolute value sign to obtain,

$-(6+9x)\leq 24$ or $(6+9x)\leq 24$

This simplifies to

$6+9x\ge -24$ and $6+9x\leq 24$

$9x\ge -24-6$ and $9x\leq 24-6$

$9x\ge -30$ and $9x\leq 18$

$x\ge -(10)/(3)$ and $x\leq 2$

$-(10)/(3)\leq x\leq2$

We write this in interval form to get,

$[-(10)/(3),2]$

QUESTION 4

The given inequality is

$|1-5a|>29$

We split the absolute value sign to get,

$-(1-5a)>29$ or $1-5a>29$

This simplifies to,

$1-5a\:<\:-29$ or $1-5a\:>\:29$

This implies that,

$-5a\:<\:-29-1$ or $-5a\:>\:29-1$

$-5a\:<\:-30$ or $-5a\:>\:28$

$a\:>\:6$ or $a\:<\:-(28)/(5)$

We write this in interval notation to get,

$(-\infty,-(28)/(5))\cup (6,+\infty)$

If a thermometer indicates 30 degrees Celsius, what is the temperature in degrees Fahrenheit?A. 24°F
B. 17°F
C. 54°F
D. 86°F

Answers

If a thermometer indicates 30 degrees Celsius, the temperature in degrees Fahrenheit is 86°F.

Boiling water measures 100 degrees in Celsius, and 212 degrees in Fahrenheit. Freezing water measure 0 degrees in Celsius, and 32 degrees in Fahrenheit.

So, if you want to convert Celsius into Fahrenheit, you will need to:
Multiply by 180/100
Add 32

Let's convert 30 degrees Celsius into Fahrenheit.
30 $*$ 180/100 = 54
54 + 32 = 86

Please help!The guidelines for a healthy adult are to maintain a Body Mass Index (BMI) between 19.5 and 24.9. A formula that relates the height of an adult to his or her weight and BMI is shown in the picture below, where h=height in inches, w=weight in pounds, and M=BMI.

1.) Find the formula that will directly calculate BMI given a person's height and weight.

2.) Chris weighs 211 pounds and has a BMI of 28.5. How many whole pounds must he gain or lose to get into the healthy BMI range?

Thank you!!

Answers

1. $h=40\sqrt{(.45w)/(M)}\Rightarrow(h^2)/(1600)=\frac{.45w}M\Rightarrow M=(720w)/(h^2)$

2. his BMI has to be reduced by 28.5-24.9=3.6

We must thus solve $(720w)/(h^2)=3.6$ thus $(720w)/(h^2)=3.6h^2/720=.005h^2$ . We can know his height using the first formula : $h=40\sqrt{(.45w)/(M)}=40\sqrt{(.45*211)/(28.5)}\approx73.01$

Hence he must lose $(73.01)^2*.005\approx26.6$ -> 27 pounds.

We check our result : $720*(211-27)/(73.01^2)\approx24.85<24.9$

To answer the first problem you are going to need to solve the equation for M (BMI). In order to do this you need to rearrange the variables h and w to one side of the equation, and M by itself on the other side. After doing this your equation should look like:
M = (0.45*w) / ((h / 40)^2)

For part 2 we must first solve for Chris' height so that we can find his healthy range. You should use the original equation for this. You should get 73.0105 inches as an answer. Now we must solve for his weight using 24.9 as the upper limit of the healthy BMI range as well as his height. You need a new formula solving for w. I am not going to put this formula here but I will just solve for W.
His healthy weight in pounds turns out to be 184.348 pounds. In order to get into this range, he must lose 211 - 184.348 = 26.6524 pounds. Since it asks how many whole pounds he must lose you should put 27 pounds as your answer.
Hope this helped!

A doctor estimates that a particular patient is losing bone density at a rate of 3% annually. The patient currently has a bone density of 1,500 kg/mg3. The doctor writers an exponential function to represent the situation. Which values should the doctor use of a and b in a function written in the form f(x)= abx, where f(x) represents the bone density after x years?

Answers

If a patient is losing bone density at the rate of 3 % annually then it will rest:
100% - 3% = 97 %, or 0.97 of a bone density.
The doctor should use a function: $f(x)= 1,500 * 0.97^(x)$
a = 1,500, b = 0.97

Solve the absolute value equation.

|x| = –15