a. periodic but not oscillatory (I.e. the hand does not oscillate or undergo oscillations).
b. periodic and also oscillatory.
c. not periodic and not oscillatory.
d. oscillatory but not periodic.
Scenario 2: The motion of a person rocking back and forth on a rocking chair to the beat of a song is:_______
a. periodic but not oscillatory.
b. periodic and also oscillatory.
c. not periodic and not oscillatory.
d. oscillatory but not periodic.
Please explain why your answers for the two scenarios are either the same or different. Your answer should include brief definitions of periodic and oscillatory (or oscillations).
Answer:
The correct answers are
a. periodic but not oscillatory (I.e. the hand does not oscillate or undergo oscillations).
b. periodic and also oscillatory.
Explanation:
Oscillatory motion are motion that involves the repeated forward and backward motion of an object or mater between two position, points or states. An oscillatory motion that repeats itself at a regular interval or cycle is a periodic oscillatory motion. Examples of periodic oscillatory motion includes, a pendulum, the upward and downward motion of a weighted spring or a sine wave
while periodic motion is the repeated movement of an object over a specific period of time. The period is the time for the motion to repeat itself measure in seconds.
The motion of the hand of the clock is periodic as it revolves round every minute, but it is in a clockwise direction hence it is not oscillatory
while the motion f a person rocking back and forth on a rocking chair to the beat of a song is periodic and oscillatory
a. kinetic energy.
b. mechanical energy.
c. chemical potential energy.
d. electromagnetic energy.
User: An example of a fossil fuel is
a. wood.
b. petroleum.
c. the sun.
d. water.
Answer:
a
Explanation:
Answer:
No, the apple will reach 4.20041 m below the tree house.
Explanation:
t = Time taken
u = Initial velocity = 2.8 m/s
v = Final velocity = 0
s = Displacement
g = Acceleration due to gravity = -9.81 m/s² = a (negative as it is going up)
Equation of motion
The height to which the apple above the point of release will reach is 0.39959 m
From the ground the distance will be 1.3+0.39959 = 1.69959 m
Distance from the tree house = 5.9-1.69959 = 4.20041 m
No, the apple will reach 4.20041 m below the tree house.
The values in the option do not reflect the answer.
The apple will not reach the friend in the tree house as it will only reach a height of approximately 1.527 m.
To determine whether the apple will reach a friend in a tree house 5.9 m above the ground, we can use the equations of motion. Since the apple is thrown vertically upward, it will experience a negative acceleration due to gravity. Using the equation h = vo*t + (1/2)*a*t^2, where h is the final height, vo is the initial velocity, a is the acceleration, and t is the time, we can calculate the time it takes for the apple to reach a height of 5.9 m. Plugging in the values, we get:
5.9 = 2.8*t + (1/2)*(-9.81)*t^2
Simplifying the equation, we have:
-4.905*t^2 + 2.8*t - 5.9 = 0
Using the quadratic formula, we can solve for t. The quadratic formula is t = (-b ± sqrt(b^2 - 4ac)) / (2a), where a = -4.905, b = 2.8, and c = -5.9.
Plugging in the values, we get:
t = (-2.8 ± sqrt(2.8^2 - 4*(-4.905)*(-5.9))) / (2*(-4.905))
After evaluating the formula, we find that the apple will take approximately 1.527 seconds to reach a height of 5.9 m. Since the apple continues to rise after reaching this height, it will not reach the friend in the tree house.