The first term of an arithmetic sequence is -5, and the tenth term is 13. Find the common difference.a. 8/9
b. 2

Answers

Answer 1
Answer: Hello,

Answer B
a_(0)=-5\na_(9)=a_(0)+9*r\n13=-5+9*r\nr= (18)/(9)=2

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Please can anyone solve 9n-10=4n+10

Answers

yes

remember you can do anything to an equaiton as long as you do it to boh sides
ad try to get unknown to one side
9n-10=4n+10
minus 4n both sides
9n-4n-10=4n-4n+10
5n-10=0+10
add 10
5n+10-10=0+10+10
5n+0=20
5n=20
divide both sies by 5
5n/5=20/5
5/5n=4
1n=4
n=4
9n-10=4n+10
+10           +10
9n=4n+20
-4n     -4n
5n =20
/5     /5
n=4

Let A={2,3} and B= {7,8}.write the power set of AxB.

Answers

A=\{2;\ 3\};\ B=\{7;\ 8\}\n\nA* B=\{(2;7);\ (2;8);\ (3;7);\ (3;8)\}\n\nPower\ set\ of\ A* B\ is\ the\ set\ of\ all\ subsets\ of\ A* B\n\n\mathbb{P}(A* B)=\{\O;\ \{(2;7)\};\ \{(2;8)\};\ \{3;7)\};\ \{(3;8)\}\n\{(2;7);\ (2;8)\};\ \{(2;7);\ (3;7)\};\ \{(2;7);\ (3;8)\};\n\{(2;8);\ (3;7)\};\ \{(2;8);\ (3;8)\};\ \{(3;7);\ (3;8)\}\n\{(2;7);\ (2;8);\ (3;7)\};\ \{(2;7);\ (2;8);\ (3;8)\};\n\{(2;7);\ (3;7);\ (3;8)\};\ \{(2;8);\ (3;7);\ (3;8)\}\n\{(2;7);\ (2;8);\ (3;7);\ (3;8)\}\}

What’s the y value for the given value of x Y=x+5; x=3

Answers

Answer:

y=8/3

Step-by-step explanation:

pictomath lol

The system of equations is coincident. What are the missing values?

-2x+5y=-12
-6x+____y=____

Answers

the equation is
-6x+15y=36, and you get the answer by multiplying the first equation by 3

What is the unit rate of 6.50

Answers

i most likely think it is 3
2.50 ur welcome! hope this helps

What is the nearest one for the number 6,846,372.205? Option 1: 6,846,372.2 Option 2: 6,846,372 Option 3: 6,846,373 Option 4: 6,846,372.3

Answers

Answer:

option 2: 6,846,372

Step-by-step explanation:

The nearest one for 6,846,372.205 would be 6,846,372

Look at the tenths place (2). It's less than 5 so we round to 6,846,372.

Option 1 is incorrect; it rounds to the tenths place.

Option 3 is incorrect; it rounded UP to 3 in the ones place.

Option 4 is incorrect; it rounds up to the tenths place.