(2) increases
(3) remains the same
Answer:
Hence the correct answer is remains the same
Explanation:
As a Ca atom undergoes oxidation to Ca2+,as follows:
Ca --- Ca 2+ + 2e-
In the process of oxidation calcium loss 2 electron only there is no change in the number of protons as well neutrons therefore there is no change in the number of neutrons in its nucleus
Hence the correct answer is remains the same
Oxidation:
Oxidation is a process in which either 1 or all following changes occurs:
1. Gaining of oxygen atoms
2. Loss of electrons
3. Loss of hydrogen atom.
4. Increasing oxidation number.
Reduction:
Reduction is a process in which either 1 or all following changes occurs:
1. Loss of oxygen atoms
2. Gaining of electrons
3. Gaining of hydrogen atom.
4. Decreasing oxidation number.
B. Produce unchanging, absolute answers
C. Give explanations for natural events
D. Understand patterns
Answer:
λ = 0.0167 m = 16.7 mm
Explanation:
The wavelength of these radio waves can be found out by using the formula for the speed of radio waves:
v = fλ
where,
v = speed of radio waves = speed of light = 3 x 10⁸ m/s
f = frequency of radio waves = 18 GHz = 18 x 10⁹ Hz
λ = Wavelength = ?
Therefore,
3 x 10⁸ m/s = (18 x 10⁹ Hz)λ
λ = (3 x 10⁸ m/s)/(18 x 10⁹ Hz)
λ = 0.0167 m = 16.7 mm
Answer:
The H2O sample has the greatest number of atoms. 1.41 moles, or (1.041 moles)*(5.023x10^23) atoms
Explanation:
We need to convert each value into moles, a count of the number of atoms/molecules.
a) 1.0 moles He
b) 0.60 moles H2
c) 20 grams K: convert to moles with the molar mass of K
(20 grams K)/(39.1 g/mole K) = 0.511 moles K
d) 8.5 mL H2O (density of H2O = 1 g/mL).
Find the mass of the H2): (8.5 ml)*(1 g/ml) = 8.5 grams H2)
Now calculate moles H2): (8.5 grams)/(18 grams/mole) = 0.473 moles H2O
e) 22.6 g KMnO4
(22.6 g KMnO4 )*(158.0 g/mole) = 0.143 moles
Now we need to take into account the number of atoms per molecule:
Molecule Atoms/Molecule Moles Atoms(moles)
He 1 1.0 1.0
H2 2 0.60 1.2
K 1 0.51 0.51
H2O 3 0.47 1.41
KMnO4 6 0.143 0.86
The H2O sample has the greatest number of atoms. 1.41 moles, or (1.041 moles)*(5.023x10^23) atoms