CHEMISTRY HIGH SCHOOL

A 1.540 gram sample of an alloy containing only tin and zinc was reacted with excess fluorine gas to produce 2.489 grams in total of a mixture of tin IV fluoride and zinc fluoride. Calculate the percent composition by mass of the two metals in the alloy.

Answers

Answer 1

Answer:

Answer:

Tin: 54.3%

Zinc: 45.7%

Explanation:

The molar masses of the elements are:

Tin: Sn = 117.710 g/mol

Zinc: Zn = 65.409 g/mol

Fluorine: F = 18.998 g/mol

The fluorine gas in excess, so the reaction consumes all the alloy, and all the tin is converted to SnF₄ and all the zinc is converted to ZnF₂. The molar masses of the fluorides are:

SnF₄ = 117.710 + 4*18.998 = 193.702 g/mol

ZnF₂ = 65.409 + 2*18.998 = 103.405 g/mol

If we call x the number of moles of SnF₄, and y the number of moles of ZnF₂, the total mass can be calculated knowing that the mass is the number of moles multiplied by the molar mass:

193.702x + 103.405y = 2.489

The number of moles of Sn is the same as SnF₄ (1:1), and also the number of moles of Zn is the same as ZnF₂ (1:1), so the mass of the alloy:

117.710x + 65.409y = 1.540

if we multiply it by -1.581 and sum with the other equation:

117.710x*(-1.581) + 65.409y*(-1.581) + 193.702x + 103.405y = 1.540*(-1.581) + 2.489

7.60249x = 0.05426

x = 0.0071 mol of Sn

117.710*0.0071 + 65.409y = 1.540

65.409y = 0.704259

y = 0.0108 mol of Zn

The masses are the molar mass multiplied by the number of moles:

Sn: 117.710*0.0071 = 0.836 g

Zn: 65.409*0.0108 = 0.704 g

The percent composition is the mass of the substance divided by the total mass multiplied by 100%:

Sn: (0.836/1.540)*100% = 54.3%

Zn: (0.704/1.540)*100% = 45.7%

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Answer:

d = 0.2 g/cm³

General Formulas and Concepts:

Density = mass / volume

Explanation:

Step 1: Define

m = 100 g

V = 500 cm³

d = ?

Step 2: Find density

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Answers

Bases produce hydroxide ions, while acids produce hydrogen ions.

Bases have a pH of above 7, and are bitter and slippery.

Answer: c. hydroxide ions

Final answer:

Bases in a solution produce hydroxide ions (OH-). This ability to donate a hydroxide ion is what characteristically defines a substance as a base.

Explanation:

When bases dissolve in water, they produce hydroxide ions (OH-). In chemistry, bases are substances that can accept hydrogen ions (H+) or donate a hydroxide ion. For example, when sodium hydroxide (NaOH), a common base, dissolves in water, it dissociates into sodium ions (Na+) and hydroxide ions (OH-). This is the characteristic that defines a substance as a base.

Bases in a solution produce hydroxide ions (OH-). This ability to donate a hydroxide ion is what characteristically defines a substance as a base

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Given that the molar mass of naoh is 40.00 g/mol, what mass of naoh is needed to make 2.500 l of a 2.000 m naoh solution? use molarity equals startfraction moles of solute over liters of solution endfraction.. 0.1250 g 5.000 g 32.00 g 200.0 g

Answers

The mass of Sodium hydroxide which is needed to make 2.500 L of a 2.000 M NaOH solution is 200 grams.

How do we calculate mass from moles?

Mass of any substance will be calculated by using their moles as:

n = W/M, where

W = required mass

M = molar mass

Given that, molarity of NaOH = 2M

Volume of NaOH solution = 2.5L

Moles of NaOH will be calculated by using the below equation as:

M = n/V

n = (2)(2.5) = 5 moles

Now we calculate the mass of NaOH of 5 moles as:

W = (5mol)(40g/mol) = 200g

Hence option (4) is correct.

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Answers

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Answers

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