Find the constant of variation for the relationship shown in the following table:Two row table. First row head is x. First row data are one, two, three, four. Second row head is y. Second row data are three, six, nine, twelve.

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A.
3

B.
4

C.
2

D.
1

Final answer:

It would take approximately 30 days for a single-cell amoeba to produce a population of about 10,000 amoebae.

Explanation:

To find out how long it would take for a single-cell amoeba to produce a population of about 10,000 amoebae, we need to calculate the number of times the amoeba doubles. Since the amoeba doubles every 3 days, we can find out the number of doubling periods it would take to reach 10,000 amoebae by dividing 10,000 by 2. This equals approximately 9.965, which means the amoeba would need to double about 9.965 times. Since we can't have a fraction of a doubling period, we can round it up to 10.

Each doubling period is 3 days, so to find out how long it would take, we can multiply the number of doubling periods (10) by the time interval for each doubling period (3 days). 10 x 3 = 30. Therefore, it would take approximately 30 days for a single-cell amoeba to produce a population of about 10,000 amoebae.

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Answer:

No solution

Step-by-step explanation:

Let's solve this equation to see if there are any solutions.

First we need to simplify it;

10 + 6x = 15 + 9x - 3x

Combine like terms:

6x - 9x + 3x = 15 - 10

0x = 5

0 = 5

Zero cannot be equal to 5, so there is no solution