If you are facing the opposite direction of the way the wave is moving, then it will be higher. But, if you are moving the same direction as the wave, it will be lower, because the frequency should go down. Hope this helps! :)
The words are:
True, false, weak electrolyte, strong electrolyte, non-electrolyte, does not, does, H+ is, OH- is, no ions are, acidic, basic, neutral.
HCN is a weak electrolyte that partially ionizes in water and forms an acidic solution as H+ ions are formed, while acetone is a non-electrolyte that does not form ions in water and the resulting solution is neutral.
It is true that when hydrogen cyanide, HCN, dissolves in water, the solution is weakly conducting and acidic in nature. This is because hydrogen cyanide, HCN, is a weak electrolyte that only partially ionizes in water, and hence does support the movement of charge, albeit to a lesser extent than a strong electrolyte. In addition, since H+ ions are specifically formed from the ionization of HCN in water, the solution is acidic.
It is false that when acetone, CH3COCH3, is dissolved in water a conducting solution results. This is because acetone, CH3COCH3, is a non-electrolyte. It does not ionize in water, and therefore does not support the movement of charge. As such, no ions are formed when acetone is dissolved in water and the solution remains neutral.
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Answer:
cooler air
Explanation:
The net ionic equation for this reaction is . In ionic equations the soluble compounds are written in their dissociated ion forms. The ionic equation can be determined by knowing the general solubility rules. In this problem there are sulfate compounds involved. It is important to know that sulfates are generally soluble except for sulfates of Ba, Pb, Ag, and Sr. Therefore, the ones dealt with in this problem, CuSO4 and FeSO4, are both soluble in water.
Further Explanation:
The complete equation for this reaction is:
CuSO4 and FeSO4 are soluble in water which will lead to the ionic equation:
Since the sulfate ion appears on both sides, it is a spectator ion. Spectator ions are unchanged in the chemical reaction and are removed from the net ionic equation:
Based on the net ionic equation it can be seen that this is a reduction-oxidation reaction. Iron was oxidized and copper was reduced.
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Keywords: ionic equation, solubility