Answer:
Two Covalent Bonds
Chemistry Concepts:
Oxygen, which is in group 6 or 16 of the periodic table, has 6 valence electrons. To achieve a full outer shell of 8 electrons, oxygen needs to gain 2 electrons or share two electrons by forming covalent bonds. Therefore, oxygen typically forms two covalent bonds with other atoms to complete its outer shell and achieve a stable electron configuration.
When oxygen forms a covalent bond with another atom, it shares one or more pairs of electrons with that atom. The shared electrons are called bonding electrons, and they are shared between the oxygen atom and the other atom. The valence electrons of the other atom also participate in the covalent bond and are shared between the two atoms.
The electrons that are not involved in bonding, known as non-bonding or lone pair electrons, remain on the oxygen atom. These electrons are still part of the valence shell of the oxygen atom and are involved in its chemical properties, but they do not participate in the covalent bond with the other atom.
Furthermore, when oxygen forms a covalent bond with another atom, both atoms share electrons, including valence electrons, to achieve a more stable electron configuration.
Learn more about Covalent Bonds:
Oxygen is in group 6 of the periodic table. In general, oxygen tends to form two covalent bonds with other atoms.
To understand why oxygen forms two covalent bonds, let's look at its electron configuration. Oxygen has 8 electrons, with 2 in its innermost shell and 6 in its outermost shell. The outermost shell can hold a maximum of 8 electrons, so oxygen needs to gain 2 more electrons to have a full outer shell.
In a covalent bond, atoms share electrons to achieve a stable electron configuration. Oxygen can share two electrons with other atoms to complete its outer shell. This means that oxygen typically forms two covalent bonds, with each bond involving the sharing of two electrons.
For example, in a molecule of water (H2O), oxygen forms two covalent bonds with two hydrogen atoms. Each bond involves the sharing of one electron from each hydrogen atom and one electron from oxygen. This sharing of electrons allows all atoms involved to have a full outer shell, making the molecule stable.
It's important to note that there can be exceptions to this general rule. In some cases, oxygen can form more than two covalent bonds, such as in molecules like ozone (O3) or sulfur dioxide (SO2). However, these cases involve different bonding arrangements and are not as common as the formation of two covalent bonds.
A)2014
B)Cl2
C)Mg
D)Mg2+
The metal loses electrons, and when it becomes Mg2+, it loses two electrons, becoming oxidized. So, the correct option is D.
Initially, the word "oxidation" was used to refer to chemical processes in which a component reacts with oxygen. An illustration of this is the oxidation of magnesium in the formation of magnesium oxide when magnesium and oxygen react.
Antoine Lavoisier used the term "oxidation" to describe the reaction of a material with oxygen. The meaning was later expanded to cover additional reactions in which electron are lost, irrespective of whether oxygen was present, after it was realised that the substance loses electrons when it is oxidised.
In the aforementioned example, the metal loses electrons; specifically, it loses two electrons as it changes from Mg+ to Mg2+, getting oxidized.
Therefore, the correct option is D
Learn more about Oxidation reaction, here:
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Answer:
Mg ²⁺
Explanation:
Τhe metal loses electrons and in forming Mg²⁺ ,it loses 2 electrons and hence oxidized.
Mg(s) ⇒ Mg²⁺ + 2e⁻
Answer:
A. testing the theory of atoms.
Explanation:
J. J. Thomson is well known scientist for discovering the electron as a part of atom's structures, which changed the perception of this matter, and it was a significant event for physics.
☃️ Chemical formulae ➝
For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.
Atomic weight of elements:
Ca = 40
C = 12
O = 16
❍ Molecular weight of
= 40 + 12 + 3 × 16
= 52 + 48
= 100 g/mol
❍ Given weight: 10 g
Then, no. of moles,
⇛ No. of moles = 10 g / 100 g mol‐¹
⇛ No. of moles = 0.1 moles
☄ No. of moles of Calcium carbonate in that substance = 0.1 moles
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B) not moving for the first 2 seconds, then begin moving and continue to gain speed.
C) slowing down for the first two seconds, then begin moving at a constant speed.
D) not moving for the first two seconds, then begin moving at the constant speed.
Answer:
According to the following position vs. Time graph the bicyclist was : D
D. Not moving for the first two seconds, then begin moving at the constant speed.
Explanation:
Along Y-axis = Distance in meters
Along X-axis = Time taken in second
Answer:
19.3 g/cm³
Explanation:
Mass = 965 g; volume = 50 cm³. So,
p = 19.3 g/cm3
V√3=3.6840315cm :))