The amount of aluminum deposited when a current of 10A is passed through a solution of aluminum salt for 1930s is 5.4 g.
An electrochemical cell converts chemical energy into electrical energy. Metals with higher negative electrode potential undergo oxidation and its ionization produces electron flow through the solution.
The weight of the metal that deposited by reduction is related to the mass of metal, current passed and time as follows:
w = z It
where z = E/96500 F
Equivalent mass of Al, E = 27 g
t = 1930 s
current I = 10 A.
Now, the weight of aluminum metal deposited is calculated as follows:
w = 1930 s × 10 A × 27/96500 = 5.4 g.
Therefore, the weight of Al deposited on the electrode is 5.4 g.
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Answer:
AL*3+ + 3e- =AL.
(10A×1930)÷96500=0.2mole e-
0.2÷3×27=1.8g(AL)
Answer:
158.0 mL
Explanation:
We can solve this problem by using Boyle's law, which states that:
"For a fixed mass of a gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume"
Mathematically:
where
p is the pressure of the gas
V is its volume
The equation can be rewritten as
where in this problem:
is the initial pressure
is the initial volume
is the final pressure
Solving for V2, we find the final volume:
mL
The difference between light reflection and refraction is simple. In reflection, the light ray striking the plane returns to the originating source or medium as the waves spring off the surface. in refraction, the waves go through the surface and it alters their speed and direction.
Reflection is the bouncing back of light when it strikes a smooth surface. Generally occurs on shinny surfaces that only allow rebounding of light without permitting penetration through it. In this process, light bounces back and returns back in the same direction.
Refraction is the bending of light rays when it travels from one medium to another. This occurs in transparent surfaces that allow bending of the ray to a different medium.
In this process, light changes path i.e travels from one medium to another.
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{335 B.C. 430 B.C. 400 B.C.}
Answer:BaCl2 + Al2(SO4)3 -->BaSO4 + AlCl3.
Explanation: