For this case we have the following expression:
Where,
k: it is a variable
What we must do is rewrite the expression in word form.
We then have to rewrite the expression:
seven less than the value of k.
Answer:
A phrase describes the variable expression k-7 is:
seven less than the value of k.
K-7= 7 less than k It's like if your wording backwards
Answer- 80 – 60 = 20, so 100 – 60 = 40 students
c
Answer:
Quarters: 7
Dimes: 9
Nickels: 14
Step-by-step explanation:
Bank --> 30 coins
Base Equations:
N+D+Q=30
5N+10D+25Q=335
Equation 1: 2Q=N
Equation 2: D=30-(N+Q)
Substitute Equation1 : D=30-(2Q+Q)
D=30-3Q
0.05(2Q)+0.10(30-3Q)+0.25Q=3.35
0.10Q+3-0.3Q+0.25Q=3.35
0.5Q+3=3.35
0.5Q=0.35
Q=7
if Q=7, N= 2*Q
N=14
D=9
Check Step:
7*25=175
14*5=70
9*10=90
175+70+90=335
Correct
To solve the problem, equations based on the relations between the number of nickels, dimes, and quarters are established. By substituting into these equations and solving them, it was determined that the bank contains 10 quarters, 20 nickels, and 0 dimes.
The student's question relates to solving a system of equations based on the given conditions regarding nickels, dimes, and quarters in a bank. Let's denote the number of quarters as q, the number of nickels as n, and the number of dimes as d. According to the problem, there are twice as many nickels as quarters, so we can write n = 2q. The total number of coins is 30, which gives us the equation n + d + q = 30. The total value of the coins is $3.35, which translates to 0.05n + 0.10d + 0.25q = 3.35. Using these three equations, we can solve for n, d, and q.
Substituting the first equation into the other two, and solving for q and d, we find that there are 10 quarters, 20 nickels, and 0 dimes. Thus, in the bank there are 10 quarters, 20 nickels, and no dimes.
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