In summary, a line is perpendicular to x + 3y = -3 if its slope is 3.
The subject requested is about finding the slope of a line that is perpendicular to the line specified by the equation x + 3y = -3. To find the slope, we'll first have to rewrite the given equation in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept.
Rewriting x + 3y = -3, we get y = -x/3 - 1. So the slope of the given line is -1/3. Now, two lines are perpendicular if and only if the product of their slopes is -1. Therefore, the slope of the line perpendicular to the given line will be -1 / original slope = -1 / (-1/3) = 3.
Thus, the slope of a line perpendicular to the line x + 3y = -3 is 3.
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Answer:
Step-by-step explanation:
You can split this irregular shape into a square and a trapezoid.
The formula for a square is:
The formula for a right trapezoid:
Area of square:
Area of right trapezoid:
Add up the individual areas to find the overall:
4 + 3 = 7
Answer
Step-by-step explanation:
To find the area of a shape multiply its height by its width. For a square you only need to find the length of one of the sides (as each side is the same length) and then multiply this by itself to find the area.
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Answer:
Table of Values: The ratio of (Y) to (X) gives the unit rate and slope.
Equation: If the equation can be written as y=mx, then m is the unit rate and the slope.
Graph: When the line passes through the origin, the slope of the graph gives the unit rate and the slope.
Step-by-step explanation:
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