Answer:
A^-1 =
[4 3/2]
[-1/3 -1/6]
Answer: [ 4 , 3/2]
[-1/3 , -1/6]
Step-by-step explanation: I did the test
The total value of gold when it was mined was $10.73.
In 1970, one ounce of gold cost $36.02. A miner found three pieces of gold in an underground mine in 1970.
The pieces weighed 0.080-ounce, 0.122 ounce, and 0.096 ounce. To find the total value of gold when it was mined, you need to multiply the weight of each piece of gold by the price per ounce in 1970 and add the results. To do so, let's find the value of each of the three pieces of gold: Value of first piece = 0.080 ounce × $36.02/ounce = $2.88Value of second piece = 0.122 ounce × $36.02/ounce = $4.39Value of third piece = 0.096 ounce × $36.02/ounce = $3.46Now, add up the value of all three pieces to find the total value of gold: $2.88 + $4.39 + $3.46 = $10.73
Therefore, the total value of gold when it was mined was $10.73.
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B) 8/7
C) -7/8
D) -8/7
Speed of father is 40 mph
Given that;
Speed of boy on bicycle = 8 mph
Total time taken by father = 15 min = 0.25 hour
Find:
Speed of father
Computation:
Distance = Speed × Time
So,
Boy's cover distance = Father's cover distance
[(Speed of boy on bicycle)(Time taken by boy)] = [(Speed of father)(Time taken by father)]
[(8)(1 + 0.25)] = [(Speed of father)(0.25)]
[(8)(1.25)] = [(Speed of father)(0.25)]
Speed of father = 10 / 0.25
Speed of father = 40 mph
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