Martina hits a volleyball ball upward with an initial velocity of 13 meters/sec. When she hits the ball, it is one meter above the ground. How long will it take the ball to hit the ground?

the ball will take 6.5 seconds to hit the ground

Final answer:

The question from the student is about time airborne for a volleyball hit upwards with an initial velocity. A physics equation of motion is utilized to solve it by inserting the values and extracting time.

Explanation:

The subject of the question is physics, specifically the subtopic of kinematics in terms of upward motion. The problem can be solved by using the equation of motion: `y = y0 + v0 * t - 0.5 * g * t²`, where y0 is the initial height, v0 is initial velocity, g is the acceleration due to gravity and t is the time taken. In this situation:

• y0 is 1 meter (the starting height of the ball).
• v0 is 13 m/s (the initial upward velocity of the ball).
• g is approximately 9.8 m/s² (the acceleration due to gravity).

Set y (the final position) to 0 (ground level), and solve for t (time taken):

0 = 1m + (13 m/s) * t - 0.5 * (9.8 m/s²) * t²

Solving this quadratic equation, we get two solutions as the time cannot be negative for this context, so choose the positive value as the time taken for the ball to hit the ground. This will give the duration the volleyball remains in the air after being hit by Martina.

Learn more about Projectile Motion here:

brainly.com/question/29545516

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