Sodium(na) is a highly reactive metal and chlorine is a poisonous gas. Which compound do they form when they chemically combine?
Answers
Sodium lose one electron and convert into sodium ion Na+
Chlorine lose one electron and form Cl- ion
When these ions come together they from an ionic compound NaCl,
table salt
The ionic compound which consist ionic bond. The ionic bond is a type of bond which formed between positive and negative ions or metal, sodium and non-metal , chlorine
Related Questions
Twelve grams of carbon-12 atoms is defined asA) one moleB) a molar volumeC) the mole ratioD) Avogadro's number
A scientist formed a theory based on an experiment he conducted. Many years later, researchers studied his experiment to see if there were any possible sources of error. Should the researchers do this?
Convert 43.0 grams of SiH4 to moles
What hypotheses could you propose about the relationship between the position of a type of atom in a molecule and the number of bonds that the atom forms?
Answers
Scientists use-
Hardness
Streak
Density
Specific Gravity
ColorCrystal Shape.LusterCleavage/Fracture
OA. rotates
OB. revolves
OC. explodes
OD
(vibrates
Reset
Submit
Answers
Answer:
revolves
Explanation:
Answers
Answer:
13.28 mol.
Explanation:
- We can use the general law of ideal gas: PV = nRT.
where, P is the pressure of the gas in atm (P = 1.32 atm).
V is the volume of the gas in L (V = 242.0 L).
n is the no. of moles of the gas in mol (n = ??? mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K).
T is the temperature of the gas in K (T = 20.0° + 273 = 293.0 K).
∴ n = PV/RT = (1.32 atm)(242.0 L)/(0.0821 L.atm/mol.K)(293.0 K) = 13.28 mol.
Answers
Answers
Answer:
1) The dilution scheme will result in a 200μM solution.
2) The dilution scheme will not result in a 200μM solution.
3) The dilution scheme will not result in a 200μM solution.
4) The dilution scheme will result in a 200μM solution.
5) The dilution scheme will result in a 200μM solution.
Explanation:
Convert the given original molarity to molar as follows.
Consider the following serial dilutions.
1)
Dilute 5.00 mL of the stock solution upto 500 mL . Then dilute 10.00 mL of the resulting solution upto 250.0 mL.
Molarity of 500 mL solution:
10 mL of this solution is diluted to 250 ml
Convert μM :
Therefore, The dilution scheme will result in a 200μM solution.
2)
Dilute 5.00 mL of the stock solution upto 100 mL . Then dilute 10.00 mL of the resulting solution upto 1000 mL.
Molarity of 100 mL solution:
10 mL of this solution is diluted to 1000 ml
Convert μM :
Therefore, The dilution scheme will not result in a 200μM solution.
3)
Dilute 10.00 mL of the stock solution upto 100 mL . Then dilute 5 mL of the resulting solution upto 100 mL.
Molarity of 100 mL solution:
5 mL of this solution is diluted to 1000 ml
Convert μM :
Therefore, The dilution scheme will not result in a 200μM solution.
4)
Dilute 5 mL of the stock solution upto 250 mL . Then dilute 10 mL of the resulting solution upto 500 mL.
Molarity of 250 mL solution:
10 mL of this solution is diluted to 500 ml
Convert μM :
Therefore, The dilution scheme will result in a 200μM solution.
5)
Dilute 10 mL of the stock solution upto 250 mL . Then dilute 10 mL of the resulting solution upto 1000 mL.
Molarity of 250 mL solution:
10 mL of this solution is diluted to 1000 ml
Convert μM :
Therefore, The dilution scheme will result in a 200μM solution.
Answers
Answer: Lysosomes
Explanation: The lysosome is an organelle that contains digestive enzymes and acts as the organelle-recycling facility of an animal cell. It breaks down old and unnecessary structures so their molecules can be reused. Lysosomes are part of the endomembrane system, and some vesicles that leave the Golgi are bound for the lysosome.