b. Covalent bonds involve the sharing of electrons between atoms; ionic bonds involve the electrical attraction between atoms.
c. Covalent bonds involve the sharing of electrons between atoms; ionic bonds involve the sharing of protons between atoms.
d. Covalent bonds involve the transfer of electrons between atoms; ionic bonds involve the sharing of electrons between atoms.
Final answer:
The difference between covalent bonds and ionic bonds is b. Covalent bonds involve the sharing of electrons between atoms; ionic bonds involve the electrical attraction between atoms.
Final answer:
In covalent bonds, atoms share pairs of electrons to achieve a stable electron configuration. This sharing creates a strong bond between the atoms, and they are typically nonmetals. In ionic bonds, there is a transfer of electrons from one atom to another, resulting in the formation of ions with opposite charges.
One atom becomes positively charged (cation), and the other becomes negatively charged (anion). The electrical attraction between these oppositely charged ions holds them together, forming an ionic bond. Ionic bonds typically form between a metal and a nonmetal.
Learn more about covalent bondshere:
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There is less energy at the end of the explosion than there is at the beginning.
There is the same amount of energy at the end of the explosion than there is at the beginning.<<<My answer
The amount of energy before and after the explosion depends on the type of reaction.
Can someone please check it?
Answer:
A. 3.36g of Na.
B. 14.62g of Ba3(PO4)2.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
3Ba + 2Na3PO4 → 6Na + Ba3(PO4)2
Next, we shall determine the mass of Ba that reacted and the mass of Na and Ba3(PO4)2 produced from the equation.
This is illustrated below:
Molar Mass of Ba = 137g/mol
Mass of Ba from the balanced equation = 3 x 137 = 411g
Molar mass of Na = 23g/mol
Mass of Na from the balanced equation = 6 x 23 = 138g
Molar mass of Ba3(PO4)2 = (3 x 137) + 2[31 + (4x16)] = 411 + 2[31 + 64] = 601g/mol
Mass of Ba3(PO4)2 from the balanced equation = 1 x 601 = 601g
Summary:
From the balanced equation above,
411g of Ba reacted to produce 138g of Na and 601g of Ba3(PO4)2.
A. Determination of the mass of Na produced by reacting 10g of Ba.
From the balanced equation above,
411g of Ba reacted to produce 138g of Na.
Therefore, 10g of Ba will react to produce = (10 x 138)/411 = 3.36g of Na.
Therefore, 3.36g of Na is produced.
B. Determination of the mass of Ba3(PO4)2 produced by reacting 10g of Ba.
From the balanced equation above,
411g of Ba reacted to produce 601g of Ba3(PO4)2.
Therefore, 10g of Ba will react to produce = (10 x 601)/411 = 14.62g of Ba3(PO4)2.
Therefore, 14.62g of Ba3(PO4)2 is produced.