Answer:
Explanation:
i just took the test
The answer is C just got it right
(2) 137Cs (4) 220Fr
Answer: The correct option is 4.
Explanation: All the options will undergo some type of radioactive decay processes. There are 3 decay processes:
1) Alpha decay: It is a decay process in which alpha particle is released which has has a mass number of 4 and a charge of +2.
2) Beta-minus decay: It is a decay in which a beta particle is released. The beta particle released has a mass number of 0 and a charge of (-1).
3) Beta-plus decay: It is a decay process in which a positron is released. The positron released has a mass number of 0 and has a charge of +1.
For the given options:
Option 1: This nuclei will undergo beta-plus decay process to form
Option 2: This nuclei will undergo beta-minus decay process to form
Option 3: This nuclei will undergo a beta minus decay process to form
Option 4: This nuclei will undergo an alpha decay process to form
Hence, the correct option is 4.
A. FeS
B. Fe2S3
C. Fe2(SO3)3
Chemical formula of iron (III) sulfide is Fe₂S₃.
A chemical formula is a way of presenting information about the chemical proportions of atoms that constitute a particular chemical compound or molecule, using chemical element symbols, numbers, and sometimes also other symbols, such as parentheses, dashes, brackets, commas and plus and minus signs.
We can write a chemical formula by following steps-
1. Write both the atoms that are present in the chemical compound.
2. Write the valencies of both the atoms that are present in the chemical compound.
3. Now cross multiply both the atoms such that 1 atom's valency goes to the subscript of another atom and vice versa.
Given,
oxidation state of Fe = +3
Valency of Fe = 3
Valency of sulphide ion = 2
When we cross multiply both the atom's valencies we get chemical formula of iron (III) sulfide as Fe₂S₃.
Therefore, chemical formula of iron (III) sulfide is Fe₂S₃.
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b. The mass of the nucleus of the atom
c. The mass of the neutrons in the atom
d. The mass of the electrons in the atom
O A. 2K+ + OH + H2SO4 → OH + 2H+ + K2SO4
B. OH + 2H+ + 2H20()
C. 2KOH + H2SO4 → 2H20 + K2SO4
D. 2K+ + OH + 2H+ + SO42- → 2H20() + 2K+ + SO42-
SUBMIT
Answer:
The answer is "Option D".
Explanation:
The entire ionic equation for all the substances, which are ionic compounds but are available in an aquatic is represented in the form with ions in the full ionic equation.
In the Net ionic equation, it doesn't have the particulate matter throughout the net ionic equations throughout the equations.
In the Spectator ions, it doesn't participate in interactions mostly on reaction and the material hand. From both sides, the very same ions are present.
The evenly balanced chemical formula is,
It is the separate organic compound that full ion formula will match the choice D.
The complete ionic equation for the reaction is 2K+ + 2OH- + 2H+ + SO42- → 2H2O + 2K+ + SO42-.
The complete ionic equation for the reaction 2KOH(aq) + H2SO4(aq) → 2H20(l) + K2SO4(aq) is:
2K+ + 2 OH- + 2 H+ + SO42- → 2 H2O(l) + 2 K+ + SO42-
The equation is balanced in terms of mass and charge by adding spectator ions (K+ and SO42-). The net ionic equation can be obtained by eliminating the spectator ions, leaving only the species that undergo a chemical change.
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