MATHEMATICS COLLEGE

12. If n(A) = 14, n(B) = 15, and n(
AB) = 6, then n(AUB) is
​

Answers

Answer 1
Answer:

Step-by-step explanation:

The above answer is right no doubt

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Answers

It’s b trust me bro

Please help the first people were wrong!!!

Answers

Answer:

The surface area is about 267.04 cm^2; the surface area would be divided by 4 if the slant height and diameter were to be cut in half

Angela can swim 480 meters in 40 minutes. What units are used to determine Angela's rate?

Answers

Answer:

Meters Per Minute (12 meters per minute)

Step-by-step explanation:

480/40 = 12

Seven more than twice a number is 23.

Answers

Answer:

x=8

Step-by-step explanation:

In other words, you are looking for a number (x) that if you multiply it by two (same as twice) and then add 7, you get 23.

To solve this, you first write the problem as an algebra equation as follows: 2x + 7 = 23

Then you solve the equation by subtracting 7 from both sides, and then divide both sides by 2. Here is the math to illustrate better:

2x + 7 = 23

2x + 7 - 7 = 23 - 7

2x = 16

2x/2 = 16/2

x = 8

Answer:

i think it is 16

Step-by-step explanation:

16 + 7 = 23

Four times the quotient of 3 and 4

Answers

Answer:

3

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

The quotient of 3 and 4 is 0.75.

3/4 = 0.75

--

0.75 x 4 = 3...

So the answer is 3.

At a farm, there are two huge pits for storing hay. 90 tons of hay is stored in the first pit, 75 tons in the second pit. Then, three times as much hay was removed from the first pit as was removed from the second pit. After that, there was half as much hay in the first pit as there was now in the second pit. How many tons of hay was taken from the first pit?

Answers

Answer:

63 tons

Step-by-step explanation:

The problem statement asks for the tons of hay removed from the first pit. It is convenient to let a variable (x) represent that amount. This is said to be 3 times the amount removed from the second pit, so that amount must be x/3.

The amount remaining in the first pit is 90-x.

The amount remaining in the second pit is 75 -x/3.

Since the first pit remaining amount is half the second pit remaining amount, we can write the equation ...

... 90 -x = (1/2)(75 -x/3)

... 180 -2x = 75 -x/3 . . . . multiply by 2

... 105 - 2x = -x/3 . . . . . . subtract 75

... 315 -6x = -x . . . . . . . . multiply by 3

... 315 = 5x . . . . . . . . . . . add 6x

... 63 = x . . . . . . . . . . . . . divide by 5

63 tons of hay were taken from the first pit.

_____

Check

After removing 63 tons from the first pit, there are 27 tons remaining. After removing 63/3 = 21 tons from the second pit, there are 54 tons remaining. 27 is half of 54, so the answer checks OK.
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