72.7% is the percent by mass of oxygen in carbon dioxide. A percent is obtained by multiplying the result by 100.
One approach to show the concentration for an element within a compound or component in a combination is as a mass percentage. The mass percentage is computed by dividing the total weight of the combination by the mass of each component and multiplying the result by 100%. The mass percent is calculated by dividing the mass that contains the compound and solute by the mass for the element or solute.
Molar mass of oxygen = 32 g/mole
Molar mass of carbon dioxide = 44 g/mole
mass percentage of oxygen =(molar mass of oxygen/molar mass of carbon dioxide)× 100
=(32/44)× 100
=72.7%
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Answer : The percent by mass of oxygen in carbon dioxide is, 72.72%
Solution : Given,
Molar mass of oxygen = 16 g/mole
Molar mass of carbon dioxide = 44 g/mole
As we know that there are 2 atoms of oxygen and 1 atom of carbon present in the carbon dioxide.
So, the molar mass of oxygen, = 2 × 16 = 32 g/mole
Now we have to calculate the percent by mass of oxygen in carbon dioxide.
Now put all the given values in this expression, we get
Therefore, the percent by mass of oxygen in carbon dioxide is, 72.72%
(2) higher boiling point and a lower freezing point
(3) lower boiling point and a higher freezing point
(4) lower boiling point and a lower freezing point
Answer:
(2) higher boiling point and a lower freezing point
Explanation:
B. Bias makes the results less reliable.
C. Bias makes the results easier to interpret.
D. Bias makes the results not publishable.
Answer:
B
Explanation:
Bias may make one side look worse than they actually are.