The bond between Br atoms in a Br2 molecule is covalent and is formed by the sharing of two valence electrons.
The bond between Br atoms in a Br2 molecule is covalent and is formed by the sharing of two valence electrons.
In a covalent bond, atoms share electrons to complete their outer electron shell. In the case of a Br2 molecule, each Br atom has 7 valence electrons and needs 1 more electron to achieve a stable octet arrangement, so they share one pair of electrons to achieve this.
The bond between Br atoms in a Br2 molecule is covalent and is formed by the sharing of two valence electrons.
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energy from sunlight?
A. Vacuole
B. Nucleus
C. Chloroplast
D. Cell Membrane
Answer:
Chloroplast
Explanation:
b. It conducts electricity when in molten form.
c.It conducts electricity when it is dissolved in water.
d.It does not conduct electricity in any form.
Answer:
D) It does not conduct electricity in any form.
Explanation:
Edge 2020 Trust
Answer:
Percentage of a sample remains after 60.0 min is 13.03%.
Explanation:
∴ k = 0.693/(t1/2) = 0.693/(20.4 min) = 0.03397 min⁻¹.
kt = ln[A₀]/[A],
where, k is the rate constant (k = 0.03397 min⁻¹).
t is the time of the reaction (t = 60.0 min).
[A₀] is the initial concentration of C-11 ([A₀] = 100.0 %).
[A] is the remaining concentration of C-11 ([A] = ???%).
∵ kt = ln[A₀]/[A]
∴ (0.03397 min⁻¹)(60.0 min) = ln(100%)/[A]
∴ 2.038 = ln(100%)/[A]
∴ 7.677 = (100%)/[A]
∴ [A] = (100%)/(7.677) = 13.03%.
So, percentage of a sample remains after 60.0 min is 13.03%.
The half-life of Carbon-11 is 20.4 minutes, meaning the quantity reduces by half every 20.4 minutes. So, after approximately 60.0 minutes (roughly three half-lives), approximately 12.5% of the original sample would remain.
Carbon-11 is a radioisotope that's widely used in medical imaging due to its radioactive properties. It has a half-life of 20.4 minutes, which means that the quantity of Carbon-11 reduces to half in every 20.4 minutes.
If we denote one half-life as t, after three half-lives (60.0 min or 3t), the ratio of the remaining sample of Carbon-11 would be 1/2 * 1/2 * 1/2 = 1/8. In other words, approximately 12.5% of the original sample would be remaining. This percentage changes a bit due to the fact that 20.4 min is slightly less than 22.2 min (which would be the exact 3 half lives).
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Answer:
The percent yield of oxygen in this chemical reaction is 73.71 %.
Explanation:
Experimental yield of oxygen gas = 115.0 g
Theoretical yield:
Mass of potassium chlorate = 400.0 g
Moles of potassium chlorate =
According to reaction, 2 moles of potassium chlorate gives 3 moles of oxygen gas.
Then 3.2653 mol of potassium chlorate will give:
Mass of oxygen gas :
Percentage yield:
The percent yield of oxygen in this chemical reaction is 73.71 %.
Answer: Step 1: List the known quantities and plan the problem. Known. 4.96 moles O2; 1 mol = 22.4
Explanation: I hope that helped.