Part B: Determine the vertex and indicate whether it is a maximum or a minimum on the graph. How do you know? (2 points)
The function H(t) = −16t2 + 90t + 50 shows the height H(t), in feet, of a projectile after t seconds. A second object moves in the air along a path represented by g(t) = 28 + 48.8t, where g(t) is the height, in feet, of the object from the ground at time t seconds.
Part A: Create a table using integers 1 through 4 for the 2 functions. Between what 2 seconds is the solution to H(t) = g(t) located? How do you know? (6 points)
Part B: Explain what the solution from Part A means in the context of the problem. (4 points)
The correct answers are:
Question 1 - Part A: f(t)=(t+3)²-29; Part B: (-3, -29), minimum; Question 2 - Part A: H(1) = 124, g(1) = 76.8; H(2) = 166, g(2) = 125.6; H(3) = 176, g(3) = 174.4; H(4) = 154, g(4) = 223.2; Part B: Between 3 and 4 seconds, because that is where the values of g(t) catch up with H(t).
Explanation:
Our quadratic function is in the form f(x)=ax²+bx+c. Our value of a is 1, b is 6, and c is -20.
To write a quadratic in vertex form, first take half of the b value and square it: (6/2)² = 3² = 9. This is what we will add and subtract to the function:
f(t) = t²+6t+9-20-9
The squared portion will be (t+b/2)²:
f(t) = (t+3)²-20-9
f(t) = (t+3)²-29
Vertex form is f(x) = a(x-h)²+k, where (h, k) is the vertex; in our function, (h, k) is (-3, -29).
Since the value of a was a positive, this parabola opens upward; this makes the vertex a minimum.
For Question 2 Part A, substitute the values 1, 2, 3 and 4 in H(t) and g(t).
For Part B, we can see that the values of g(t) are much less than that of H(t) until 3 seconds. From there, we can see that g(t) passes H(t). This means that the solution point, where they intersect, is between 3 and 4 seconds.
Answer:
c
Step-by-step explanation:
Slope intercept form:
The equation of straight line is given by:
....[1]
where, m is the rate or slope and b is the initial value of y-intercept.
As per the statement:
A certain species of tree grows an average of 3.1 cm per week.
Let x be the number of week and y represents the weekly height of the tree.
then;
" tree grows an average of 3.1 cm per week." translated to 3.1 x
It is also given that:
the measurements begin when the tree is 400 centimeters tall.
⇒y(0) =b = 400 cm
Substitute the given values in [1] we have;
Therefore, an equation for the sequence that represents the weekly height of this tree in centimeters is,
box to the tower. How tall is the tower now? Give your answer
in centimetres (cm).
Answer:
126 cm
Step-by-step explanation:
each block is 112/8 cm tall=14cm
112cm is the current tower
add one more block +14cm is 126 cm total
Answer:
97.50
Step-by-step explanation:
9.75(3) + 9.75(7);
9.75(3+7); 97.50
The sum of the geometric progression up to the 6th term is 512/7
To find the sum of a geometric series, you can use the formula for the sum of a finite geometric series:
Where:
- Sₙ is the sum of the first n terms of the series.
- a is the first term of the series.
- r is the common ratio.
- n is the number of terms in the series.
In your case, you have the geometric series: 16, 2, 1/4, ...
1. Identify the values for the formula:
- The first term (a) is 16.
- The common ratio (r) is found by dividing the second term by the first term: 2/16 = 1/8.
- You want to find the sum of the first 6 terms (n = 6).
2. Plug these values into the formula and calculate S₆:
S₆ = (16(1 - (1/8)⁶))/(1 - 1/8)
Now, calculate the individual terms in the formula:
S₆ = (16(1 - 1/262144))/(7/8)
S₆ = (16(262143/262144))/(7/8)
S₆ = ((4194288/262144)/(7/8)
Now, perform the division:
S₆ = (4194288/262144) \* (8)/(7)
S₆ = 64 * 8/7
Now, multiply:
S₆ = 512/7
So, the sum of the geometric progression up to the 6th term is 512/7
Learn more about geometric series here
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f (9) = 5 - 2 (9)
f (9) = 5 - 18
f (9) = - 13
f (9) + 3 = - 13 + 3
f (9) + 3 = - 10
Answer:
the answer is -10
Step-by-step explanation: