MATHEMATICS HIGH SCHOOL

Guillmero wants to purchase a new controller for his video game System. He has a $10 off coupon for big electronics. At costmart there is a 25% off sale on any item . regular price for the controllers at both stores is $49.99. Write an inequality and tell where guillermo will get the better price.

Answers

Answer 1
Answer: If you would like to know where Guillmero will get the better price, you can calculate this using the following steps:

a coupon: $49.99 - $10 = $39.99

Costmart: 25% of $49.99 = 25% * 49.99 = 25/100 * 49.99 = $12.4975 = $12.50
$49.99 - $12.50 = $37.49

Guillmero will get a better price at Costmart.

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(8 7/8 + 2 1/3 + 4 1/4) - (3 3/4 - 1 1/2)

Answers

Answer:

13 5/24

Step-by-step explanation:

Firstly, turn all mixed fractions into improper ones:

(8 7/8 + 2 1/3 + 4 1/4) - (3 3/4 - 1 1/2)

(71/8 + 7/3 + 17/4) - (15/4 - 3/2)

Now use GCF to find a denominator that suits all fractions:

8 : 8, 16, 24

3 : 3, 6, 9, 12, 15, 18, 21, 24

4 : 4, 8, 12, 16, 20, 24

The GCF of the first three fractions are 24. Simply add them all:

(213/24 + 56/24 + 102/24) - (15/4 - 3/2)

(371/24) - (15/4 - 3/2)

Now find the GCF of the remaining two fractions:

4 : 4

2 : 2, 4

The GCF of the last two fractions are 4, now add them all as well:

15/4 - 6/4

9/4

(371/24) - (6/4)

Now find the GCF:

24 : 24

4 : 4, 8, 12, 16, 20, 24

(371/24 - 36/24)

317/24

Now turn it into a mixed number:

13 5/24

Let f(x) = -2x^2 and g(x) = 2x - 4. On the set of axes, draw the graphs of y = f(x) andy = g(x).
Using this graph, determine and state all values of x for which f(x) = g(x).

Answers

f(x) = -2x²
g(x) = 2x - 4

                              f(x) = g(x)
                             -2x² = 2x - 4
                       -2x² - 2x = 2x - 2x - 4
                 -2x² - 2x + 4 = -4 + 4
                 -2x² - 2x + 4 = 0
       -2(x²) - 2(x) - 2(-2) = 0
                 -2(x² - x - 2) = 0
                          -2         -2
                      x² - x - 2 = 0
              x² + 2x - x - 2 = 0
x(x) + x(2) - 1(x) - 1(2) = 0
        x(x + 2) - 1(x + 2) = 0
                (x - 1)(x + 2) = 0
   x - 1 = 0    or    x + 2 = 0
     + 1 + 1              -  2 -  2
         x = 1      or       x = -2          
                             f(x) = g(x)
                            -2x² = 2x - 4
                        -2(-2)² = 2(-2) - 4
                           -2(4) = -4 - 4
                                -8 = -8
                                   or
                              f(x) = g(x)
                             -2x² = 2x - 4
                          -2(1)² = 2(1) - 4 
                                -2 = 2 - 4
                                -2 = -2

Solution Sets: {(-2, -8), (1, -2)}

4. Solve the quadratic by factoring, isolating x^2, or using the quadratic formula:a. 2x^2 – 7x = 4

b. 81x^4 – 1


c. 2x^2 – 32 = 0

d. X^2 – 7x + 12

Answers

Hello,

A:
2x²-7x-4=0
==>2x²-8x+x-4=0
==>2x(x-4)+1(x-4)=0
==>(x-4)(2x+1)=0
==>(x=4) or (x=-1/2)

B: where is the sign "=" !!!!!!!!!!!!!!!!!!

81x^-1=(9x²+1)(3x+1)(3x-1) I can not go any further.


C)
2x²-32=0
==>x²-16=0
==>(x+4)(x-4)0
==>x=-4 or x=4

D:
where is the sign "="!!!!!!!!!!!!!!!!!!!!!!!!

x^2-7x+12=(x-4)(x-3) but I can not go ant further....

A gardener weeds 2/3 of a flower bed in 6 min. How much of the flower bed did the gardener weed in 1 min?

(50 pts) (This is my own experiment 2 see how fast Brainly is and how efficient!)

Answers

(2/3 bed) / (6min) = ('x' bed) / (1min)

Cross-multiply:

             (2/3 bed * 3min) = ('x' bed * 6min)

Divide each side by 6min:

                 1/3 bed = 'x' bed

You're not getting any data about the speed or efficiency of Brainly,
because you're not getting any information about how long an answerer
takes to figure out a problem or write an answer.  You're just equating
the site with the people that make it work.

Factor 3x^2y^2 − 2xy^2 − 8y^2. Show your work.

Answers

3 x^(2) y^(2) -2x y^(2) -8 y^(2) \n = 3 x^(2) y^(2) -6x y^(2)+4x y^(2) -8 y^(2) \n =(3 x^(2) y^(2) -6x y^(2))+(4x y^(2) -8 y^(2)) \n =3xy^(2) (x-2)+4 y^(2)(x-2) \n =(3xy^(2)+4 y^(2))(x-2) \n = y^(2) (3x+4)(x-2)

Cos A/1-tan A + sin A/1-cot A =sin A + cos A

Answers

(cosA)/( (cosA)/(cosA)- (sinA)/(cosA))+ (sinA)/( (sinA)/(sinA)- (cosA)/(sinA) )=sinA+cosA\n (cosA)/( (cosA-sinA)/(cosA)+ (sinA)/( (sinA-cosA)/(sinA) ) )=sinA+cosA\n ( cos^(2)A )/(cosA-sinA) }- (sin^(2)A )/(cosA-sinA)=sinA+cosA\n ( cos^(2)A-sin^(2)A )/(cosA-sinA)=sinA+cosA\ncos(2A)=(sinA+cosA)(cosA-sinA)\n cos(2A)=(sinA+cosA)(sinA-cosA)\ncos(2A)=sin^(2)A - cos^(2)A\ncos2A=cos2A \n1=1
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