The larger of two numbers is 1 more than twice the smaller. The sum of the numbers is 20 less than three times the larger. Find the numbers.
I NEED help please. I'm getting extremely frustrated!!
Answer:
13 and 6
Step-by-step explanation:
Let x = larger number
Let y = smaller number
The larger of two numbers is: x =
one more than twice the smaller: 2y + 1
x = 2y + 1 {equation 1}
The sum of the numbers is: x + y =
20 less than three times the larger: 3x - 20
x + y = 3x - 20
This can be simplified. Subtract 3x from both sides.
x - 3x + y = -20
-2x + y = -20 {equation 2}
Since we already know from equation 1 that x=2y+1, substitute that into equation 2
and solve for y:
-2(2y+1) + y = -20
-4y - 2 + y = -20
-3y - 2 = -20
-3y = -18
y = -18/(-3)
y = 6
x = 2y+1 = 2(6)+1 = 12 + 1 = 13
Your numbers are 13 and 6
6k + 10.5 = 3k + 12
Answer: 0.5
Step-by-step explanation:
The given equation:
To solve the above equation for k , we first subtract 3k from both the sides , we get
Subtract 10.5 from both sides
Divide 3 on both the sides , we get
Hence, solution to the linear equation : k = 0.5
8 inches
7 inches
6 inches
Answer:
P is at (2, 7), and Q is at (6, 11).
The midpoint of PQ is at (4, 9), calculated as follows:
((2 + 6)/2, (7 + 11)/2) = (8/2, 18/2) = (4, 9)
Answer:
Step-by-step explanation:
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