The length of the deck will be equal to 15 feet.
A quadrilateral with four right angles is a rectangle. It can alternatively be described as a parallelogram with a right angle or an equiangular quadrilateral, where equiangular denotes that all of its angles are equal.
Since rectangles have two pairs of equal-length sides, for any rectangle with length L and width W,
its perimeter is always 2L + 2W (or 2(L + w), whichever you prefer). Here, we're told that the width is 4 feet less than the length.
Symbolically, we'd say that W = L - 4. This allows us to write the perimeter entirely in terms of length if we replace our W with the expression on the right side:
2L + 2W = 2l + 2(L - 4) = 2L +2L - 8 = 4L - 8
This expression to come out to 52, the equality 4L - 8 = 52 and solve for L to find what the length has to be:
Adding 8 to either side, the equality becomes 4L = 60. Diving either side by 4 gives us L = 15, which tells us that the length of the deck should be 15 feet.
Therefore, the length of the deck will be equal to 15 feet.
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Since rectangles have two pairs of equal-length sides, for any rectangle with length L and width W, its perimeter is always 2L + 2W (or 2(L + w), whichever you prefer). Here, we're told that the width is 4 feet less than the length. Symbolically, we'd say that W = L - 4. This allows us to write the perimeter entirely in terms of length if we replace our W with the expression on the right side:
2L + 2W = 2l + 2(L - 4) = 2L +2L - 8 = 4L - 8
Sam wants this expression to come out to 52, so we can set up the equality 4L - 8 = 52 and solve for L to find what the length has to be:
Adding 8 to either side, the equality becomes 4L = 60. Diving either side by 4 gives us L = 15, which tells us that the length of the deck should be 15 feet.
x ≥ 1
x ≤ 1
All real numbers
y ≤ 2
B 4:36
C 1:3
D 1:27
Scaled figures are zoomed in or zoomed out (or just no zoom) versions of each other. The correct option is D.
Scaled figures are zoomed in or zoomed out (or just no zoom) versions of each other. They have scaled versions of each other, and by scale, we mean that each of their dimension(like height, width etc linear quantities) are constant multiple of their similar figure.
So, if a side of a figure is of length L units, and that of its similarfigure is of M units, then:
where 'k' will be called a scale factor.
The linear things grow linearly like length, height etc.
The quantities which are squares or multiple linear things twice grow by the square of the scale factor. Thus, we need to multiply or divide by k²
to get each other corresponding quantities from their similar figures' quantities.
So the area of the first figure = k² × the area of the second figure
Similarly, increasing product-derived quantities will need increased power of 'k' to get the corresponding quantity. Thus, for volume, it is k cubed. or
The volume of the first figure = k³ × volume of the second figure.
It is because we will need to multiply 3 linearquantities to get volume, which results in k getting multiplied 3 times, thus, cubed.
Given that the diameter of sphere A is 2 units, it is dilated by a scale factor of 3 to create sphere B. Therefore, the diameter of sphere B is,
Diameter of sphere B = 3 × Diameter of sphere A
= 3 × 2 units
= 6 units
Now, the ratio of diameters of the sphere and the volume of the sphere can be written as,
Hence, the correct option is D.
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Answer:
1:27
Step-by-step explanation:
I will use solve in terms of pi
Know that Original volume * scale factor cubed = new volume.
The scale factor is 3 and 3^3 is 27,
Therefore the ratio is 1:27