Suppose, John arranges stack of Gold and Silver coins in such a way that each stack either contains Gold or contains Silver coins only.
He also tries to arrange them in the least area.
Here, the number of coins in each stack is the common factor of number of Gold and Silver coins.
If we find the highest common factor, then the area occupied by the coins will be least.
Hence, in this situation, we have to find the common factor.
Suppose, George and David are walking along the circular pathway of a park with different speeds.
The problem is to find the time after which they will meet again at the starting point.
Clearly, here the required time is the common multiple of independent time taken by both.
In general, Profit is the difference of Total Sales and Total Expences.
In formula form we could write it,
Profit = Total Sales - Total Expences.
According to given problem, sales increase by $1500 in a week.
That is some more sales also added to previous sales but still some expences are included in total sales and even in increased sale $1500.
So, in order to get the net profit, we need to subtract all expences (even the original cost in making the product and expences of all servises provided in sales).
Therefore, we could finally say, "if sales increase by $1500 in a week, profit would not increase by about $1500".
The center of the circle is (2, - 1) and the radius is 6 units.
The equation for a circle has the generic form x² + y² + 2gx + 2fy + c = 0.
The standard equation of a circle is x² + y² = r².
The polar form of the equation of the circle is (rcosθ)² + (rsinθ)² = p².
Given, The equation of a circle is x² + y² - 4x + 2y - 31 = 0.
We know, In x² + y² + 2gx + 2fy + c = 0, The center of the circle is,
(- g, - f) and radius is .
Therefore, 2gx = - 4x and 2fy = 2y.
2g = - 4 and 2f = 2.
g = - 2 and f = 1.
- g = 2 and - f = - 1.
So, The center is (2, - 1).
And the radius is, .
= .
= .
= 6 units.
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Answer:
centre = (2, - 1), radius = 6
Step-by-step explanation:
Rearrange the equation by placing the x and y terms together and adding 31 to both sides
Given
x² + y² - 4x + 2y - 31 = 0, then
x² - 4x + y² + 2y = 31
Use the method of completing the square
add ( half the coefficient of the x/y term )² to both sides
x² + 2(- 2)x + 4 + y² + 2(1)y + 1 = 31 + 4 + 1
(x - 2)² + (y + 1)² = 36
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r the radius
compare to (x - 2)² + (y + 1)² = 36, then
centre = (2, - 1) and r = = 6
At x = -2, the graphs of equations 2x - y = 6 and 5x + 10y = -10 intersect at the point (-2,-2).
A graph is a visual representation that shows the relationships between two or more items or values. It typically involves plotting points and connecting them to form a diagram.
To find the point of intersection of the graphs of equations 2x - y = 6 (i) and 5x + 10y = -10 (ii), we can follow these steps:
List out the points that satisfy each equation:
For equation (i):
For equation (ii):
Plot the points on a graph and join them to get the graph of each equation.
Identify the point(s) of the intersection of the two graphs. From the graph, we see that the two graphs intersect at the point (-2,-2).
Therefore, we can conclude that at x = -2, the graphs of equations 2x - y = 6 and 5x + 10y = -10 intersect at the point (-2,-2).
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Answer:
The solution to the equation is: (x,y) = (2,-2) If that helps
Step-by-step explanation:
// Solve equation [1] for the variable y
[1] y = 2x - 6
// Plug this in for variable y in equation [2]
[2] 5x + 10•(2x-6) = -10
[2] 25x = 50
// Solve equation [2] for the variable x
[2] 25x = 50
[2] x = 2
// By now we know this much :
x = 2
y = 2x-6
// Use the x value to solve for y
y = 2(2)-6 = -2
Solution :
{x,y} = {2,-2}