Answer:
To solve this problem, we can use the calorimetry formula that relates the heat transfer between the system and the surroundings:
Q = mc∆T
where Q is the heat transfer, m is the mass, c is the specific heat capacity, and ∆T is the temperature change.
We can assume that the heat lost by the glass and the calorimeter is equal to the heat gained by the water. Therefore, we can write:
Qglass + Qcalorimeter = Qwater
Substituting the values given in the problem, we get:
mglass x 0.8372 x (26.6 - 90) + 7 x 1.23 x (26.6 - 24.3) = 75 x 4.184 x (26.6 - 24.3)
Solving for mglass, we get:
mglass = 10.8 g
Therefore, the mass of the glass was 10.8 g.
I hope this answer helps you understand how to use the calorimetry formula to find the mass of an object. Thank you for chatting with me.
If we have 3.50 moles of hydrogen and 5.00 moles of nitrogen to produce ammonia, 39.66g ammonia is produced.
Avogadro's number is the number of units in one mole of any substance and equals to 6.02214076 × 10²³. The units can be electrons, atoms, ions, or molecules.
No. of moles is defined as a particular no. of particles that we can calculate with the help of Avogadro’s number.
Mass of a particular product is also find out by stoichiometry of a reaction as per the no. of mole given in the reaction.
Given,
3H₂ + N₂ --> 2NH₃
3.50 moles of hydrogen
5.00 moles of nitrogen
Limiting reagent for the reaction is H₂.
3 moles of H₂ produce 2 moles NH₃
1 moles of H₂ produce 2/3 moles NH₃.
3.5 moles of H₂ produce (2÷3)×3.5 moles NH₃ = 2.33 moles
1 mole of NH₃ = 17g of NH₃
2.33 mole of NH₃ = 39.66g of NH₃
Therefore, If we have 3.50 moles of hydrogen and 5.00 moles of nitrogen to produce ammonia, 39.66g ammonia is produced.
Learn more about mole concept, here:
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The heat of combustion (Hc0) is the amount of energy released as heat when a compound completely burns with oxygen under standard conditions.
3.05988g. grams of propane must be burned to raise the temperature of a 10.0 kg block of copper from 25.0°C to 65.0°C.
q=m*c*(change of T)
q=10000g(0.385J/g*c)*(65.0C-25.0C)or (338.2 K-298.2K)
q=154000J
154000J*(1 mol/2220 KJ)=69.36936 x mol
here's where I'm stuck
0.069369 mol
and i know that for every 1 mol there is 44.11g of C3H8.
0.069369 mol* (44.11g C3H8)/1mol = 3.05988g.
To learn more about : Heat of combustion
Ref : brainly.com/question/25109613
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Answer:
Explanation:
q = (mass) (temp change) (specific heat)
q = (10000 g) (40 °C) (0.385 J/g⋅°C) = 154000 J = 154 kJ
154 kJ / 2220 kJ/mol = 0.069369369 mol
0.069369369 mol times 44.0962 g/mol = 3.06 g (to three sig figs)
answer choice 4
b) the metals strips
c) amount of rust
d) hydrochloric acid
Answer:
b) the metals strips
Explanation:
In an experimental design, an independent variable is a variable that is changed or manipulated in a series of experiments. An independent variable is not dependent on any other variable in the experiment. The hypothesis for this experiment is stated to be: "If the chemical activity of the metallic wrapper is increased, then less rusting of iron will occur. The independent variable relates to the type of metal wrapping strip, and the dependent variables are the amount of rusting and color of the water.
Answer:
Need the choices before i can give answers thanks
Explanation: