50 balls are number 1 to 50 and a red dot is painted on those balls that are a multiple of 7. The balls are mixed into a bag and one ball is randomly chosen. What is the probability that the ball is numbered with a multiple of 5 or has a red dot?

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Answer 1

Answer: Hello,

The multiples of 7 are 7,14,21,28,35,42,49 : 7 balls
The multiples of 5 are 5,10,15,20,25,30,35,40,45,50 :10 balls
In total there are 50 balls
But there is a commun ball 35

p=(7+10-1)/50=16/50=8/25=0.32

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Use the Law of Sines to solve for all possible triangles that satisfy the given conditions. (If an answer does not exist, enter DNE. Round your answers to one decimal place. Below, enter your answers so that ∠B1 is larger than ∠B2.) a = 31, c = 42, ∠A = 39° ∠B1 = ° ∠B2 = ° ∠C1 = ° ∠C2 = ° b1 = b2 =

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Answer:

Step-by-step explanation:

In triangle ABC we have $a = 31, c = 42, ∠A = 39°$

To find other sides and angles.

Use sine formula for triangles

$(a)/(sin A) =(b)/(sin B) =(c)/(sinC) \n(31)/(sin39) =(b)/(sinB) =(42)/(sinc)$

Cross multiply to get

$Angle C =58.5^(o)$ or $121.5$

Angle B = 180-A-C

= $82.5^(o)$ or $19.5$

b =18.84 or 16.44

There are two triangles

with

$Side a = 31\nSide b = 48.84\nSide c = 42\nAngle ∠A = 39° \nAngle ∠B = 82.50° \nAngle ∠C = 58.5°$

$Side a = 31\nSide b = 16.44204\nSide c = 42\nAngle ∠A = 39° \nAngle ∠B = 19.5° \nAngle ∠C = 121.5°$

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Answers

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