An observation deck extends 314 feet out above a valley. The deck sits 264 feet above the valley floor. If an object is dropped from the observation​ deck, its height h in​ feet, after t​ seconds, is given by h equals negative 16 t squared plus 264. How long will it take for the object to be 8 feet above the valley​ floor?

Answers

Answer 1
Answer:

Final answer:

Using the quadratic equation h = -16t² + 264 which represents the object's height after time, we find that it will take 4 seconds for the object to reach 8 feet above the valley floor.

Explanation:

In this case, you're asked to find out how much time it takes for an object dropped from an observation deck to drop to a point 8 feet above the valley floor. The height h, in feet, after time t, in seconds, is represented by the quadratic equation h = -16t² + 264. Set the equation equal to desired height, which is 8 feet in this case. So, you have -16t² + 264 = 8. Rearranging, you get -16t² = 8 - 264, or -16t² = -256. Divide by -16 yields, t² = 16. The principal square root of 16 is t = 4.

Therefore, it will take 4 seconds for the object to be 8 feet above the valley floor.

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F(x)=4x^2+7x+18 find f (-9)

Answers

Answer: f(-9)= 243

Step-by-step explanation:

f(x) = 4x²+7x -18

f(-9) = 4(-9)²+7(-9)-18

= 4(81) -63-18

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Which set of lengths might be used to represent the sides of a right triangle? A. (6, 7, 10)

B. (7, 15, 17)

C. (9, 12, 16)

D. (7, 24, 25)

Answers

The set of side lengths (7, 15, 17) represents a right angled triangle

For the given set of side lengths to represent a right angled triangle, the

Pythagoras relation should be satisfied by the side lengths of the triangle.

We can write the given relation as -

h² = b² + p²

Consider the side length pairs as -

(7, 15, 17)

We can arrange the sides as -

17² = 15² + 7²

289 = 225 + 49

289 = 289

The set of side lengths (7, 15, 17) represents a right angled triangle.

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Answer:

Step-by-step explanation:

B

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Answers

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Answers

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Answers

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Step-by-step explanation:

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Answer:

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Step-by-step explanation: