Nell's mortgage is $50,150 at 10 percent for 30 years. What is her monthly payment if she must pay 8.78 points per $1,000? (Points : 1) $440.32
$439
$422.95
$385.89
Answers
The monthly payment given based on its computation was $440.10. The closest answer is 440.32.
The difference in decimal point is due to the rounding off of 8.78 points to 8.8 points in the calculator.
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The pay, P, at a certain job is calculated by the formula P=Bh, where B is the base pay an h is the number of hours worked. If an employee works more than40 hours in a week, the formula changes to P=40B+1.5B(h-40). If Susan had a base pay of $6.35 and worked 28 hours, what would be his pay for the week?
How do you convert celsius into fahrenheit?
(-1)/(-7)
(-1)/7
-(1/7)
1/(-7)
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Answer:
it's a,c,d like if this helps
Answer:
(-1)/7
1/(-7)
-(1/7)
These two equations will be equal to -1/7 as
(-1)/7=-1/7
1/(-7)=-1/7(THE SIGN OF THE DENOMINATOR WILL BE GIVEN TO THE NUMERATOR IF NEGATIVE)
-(1/7)=-1/7 (When we avoid the bracket the answer will be equalent)
Answers
b. Find the length of side a to two decimal places in three different ways.
2. Solve the triangles below.
Answers
A) b = 10.57
B) a = 22.66
#2)
A) a = 1.35 (across from the 15° angle)
∠C = 50.07° (the angle at the top of the triangle)
∠B = 114.93°
B) ∠A = 83°
b = 10.77 (across from angle B)
a = 15.11 (across from angle A)
Explanation
#1)
A) Since b is across from the 25° angle and we have the hypotenuse, we have the information for the sine ratio (opposite/hypotenuse):
sin 25 = b/25
Multiply both sides by 25:
25*sin 25 = (b/25)*25
25*sin 25 = b
10.57 = b
B) We will first use the cosine ratio. Side a is the side adjacent to the angle and we have the hypotenuse, and the cosine ratio is adjacent/hypotenuse:
cos 25 = a/25
Multiply both sides by 25:
25*cos 25 = (a/25)*25
25*cos 25 = a
22.66 = a
Now we will use the Pythagorean theorem. We know from part a that side b = 10.57, and the figure has a hypotenuse of 25:
a²+(10.57)² = 25²
a² + 111.7249 = 625
Subtract 111.7249 from both sides:
a²+111.7249-111.7249=625-111.7249
a² = 513.2751
Take the square root of both sides:
√a² = √513.2751
a = 22.66
#2)
A) Let A be the 15° angle, B be the angle to the right and C be the angle at the top of the triangle. This means side a is across from angle A, side B is across from angle B, and side c is across from angle C.
Using the law of cosines,
a²=3²+4²-2(3)(4)cos(15)
a²=9+16-24cos(15)
a²=25-24cos(15)
a²=1.8178
Take the square root of both sides:
√a² = √1.8178
a = 1.3483≈1.35
Now we can use the Law of Sines to find angle C:
sin 15/1.35 = sin C/4
Cross multiply:
4*sin 15 = 1.35* sin C
Divide both sides by 1.35:
(4*sin 15)/1.35 = (1.35*sin C)/1.35
(4*sin 15)/1.35 = sin C
Take the inverse sine of both sides:
sin⁻¹((4*sin 15)/1.35) = sin⁻¹(sin C)
sin⁻¹((4*sin 15)/1.35) = C
50.07 = C
To find angle B, add angle A and angle C together and subtract from 180:
B=180-(50.07+15) = 180-65.07 = 114.93
B) To find angle A, add angle B and angle C together and subtract from 180:
180-(52+45) = 180-97 = 83
Now use the Law of Sines to find side b (across from angle B):
sin 52/12 = sin 45/b
Cross multiply:
b*sin 52 = 12*sin 45
Divide both sides by sin 52:
(b*sin 52)/(sin 52) = (12*sin 45)/(sin 52)
b = 10.77
Find side a using the Law of Sines:
sin 83/a = sin 52/12
Cross multiply:
12*sin 83 = a*sin 52
Divide both sides by sin 52:
(12*sin 83)/(sin 52) = (a*sin 52)/(sin 52)
15.11 = a
Answers
Answer: The answer is true.
Step-by-step explanation: We are to check whether a major arc of a circle is also minor arc or not.
In the attached figure, A major arc AB is drawn on a circle with centre 'O'. The, we can easily see from there that the major arc AB corresponds to another arc AB which is smaller in length than the major arc AB.
This smaller arc is called the minor arc AB. This explains the existence of a minor arc whenever there is a major arc on a circle.
Thus, the given statement is true.
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Make sure you make a new and hard paper
Make at least 20 more mcqs
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The exam carefully to avoid errors and ensure that the questions are clear and concise.
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