MATHEMATICS HIGH SCHOOL

Two towns are 1,100 miles apart. A group of hikers Starts from each town and walks down the trail toward each other. They meet after a total hiking time of 240 hours. If one group travels 2 1/2 mile per hour slower than the other group, find the rate of each group.

Answers

Answer 1
Answer:

Answer:

3.54 and 1.04

Step-by-step explanation:

Given:

Two towns are 1,100 miles apart.

A group of hikers Starts from each town and walks down the trail toward each other..

They meet after a total hiking time of 240 hours.

If one group travels 2 1/2 mile per hour slower than the other group.

Question asked:

Find the rate of each group.

Solution:

Let speed of faster hiker = x\ mph

Speed of slower hiker = x-(5)/(2)\ mph

As we know:

Distance=speed* time

Total distance between two town = Total combined speed of both hikers *Total combined time taken

1100=(x+x-(5)/(2) )*240\n \n Dividing\ both\ sides\ by\ 240\n \n 4.58=(x+x-(5)/(2) )\n \n 4.58=2x-(5)/(2) \n \nAdding\ both\ sides\ by\ (5)/(2) \n \n 4.58+ (5)/(2)=2x- (5)/(2)+ (5)/(2)\n \n (2*4.58+5)/(2) =2x\n \n (14.16)/(2) =2x\n \n By \ cross\ multiplication\n \n 2*2x=14.16\n \n 4x=14.16

By\ dividing\ both\ sides\ by \ 4\n \n x=3.54\ miles\ per\ hour

Speed of faster hiker = x\ mph = 3.54 miles per hour.

Speed of slower hiker = x-(5)/(2)\ mph=

3.54-(5)/(2) =3.54-2.5=1.04\ miles\ per\ hour

Therefore, speed of faster hiker is 3.54 miles per hour and speed of slower hiker is 1.04 miles per hour.

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Answers

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Answers

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Answers

Answer:

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Answer:

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