Football player A has a mass of 210 pounds and is running at a rate of 5.0 mi/hr. He collides with player B. Player B has a mass of 190 pounds and is running in the same direction at 3.0 mi/hr. Which of the following statements is true?-The momentum of player A is equal to that of player B.
-The momentum of player A is greater than that of player B.
-The momentum of player A is less than that of player B.
Answers
Answer:
the momentum of player A is greater than player B.
Therefore, Option 2 is correct.
Step-by-Step explanation:
We have been given the velocity of the players and mass of the players.
Player A:
Velocity is 5m/hr
Mass 210 pounds
Player B:
Velocity is 3m/hr
Mass 190 pounds
We have a formula for momentum:
p is momentum
m is mass
v is velocity
We will find momentums for both the players:
Momentum of player A:
on substituting the values we get:
Momentum of player B:
on substituting the values we get:
Hence, the momentum of player A is greater than player B.
Therefore, Option 2 is correct.
The equation for momentum is p = mv where p is the omentum, m is the mass and v is the velocity. Calculating the momentum for each football player, player A will have a momentum of 1050 lb-mi/h and player B will have a momentum of 570 lb-mi/h. Therefore, momentum of player A is greater than that of player B.
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