Which polynomial equations have -i as one of their roots? 1. x^3 + 5x^2 - 20 = 0

2. x^3 - x^2 + x - 1 = 0

3. x^3 + 3x^2 + x + 3 = 0

4. x^3 - 2x^2 + x - 2 = 0

5. x^3 - 6x^2 - 16x + 96 = 0

Answers

Answer 1
Answer: i = sqrt(-1)
i^2 = -1
(-i)^2 = (-i)(-i) = i^2 = -1
(-i)^3 = (-i)(-i)(-i) = (-i)(i^2) = i

use these facts to find which equation is correct if x = -i

i bet on 2,3 or 4

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Y-1/x+3=-3/4 how do you solve for y

Answers

( y-1)/(x+3) =- (3)/(4)\n \nx+3\neq 0\n \nx\neq -3 \n \nD=R\setminus \left \{ -3 \right \}

4(y-1)=3(x+3)\n \n4y-4=3x+9\n \n4y=3x+9+4\n \n4y=3x+13\ \/:4\n \ny=(3)/(4)x +(13)/(4)


Find the slope of the line that passes through (3,7) and (5,4)

Answers

Answer:

-3/2

Step-by-step explanation:

y2-y1/x2-x1

7-4/3-5

3/-2

-3/2

How far from zero would you move on the x-axis to reach the point (10,8)

Answers

Answer:

You would move 10 units to the right from zero on the x-axis

Answer:

10 spaces to the right to get to 10 and up 8 to get to 8

Using graph paper, determine the line described by the given point and slope. Click to show the correct graph below. (0,6) and -1​

Answers

Answer:

Can't tell

Step-by-step explanation:

Hear me out. There is no graph hear, so I can't answer. Just letting you know

If ΔABC is similar to ΔDEF, the m∠A = 50°, and m∠E = 70°, what is m∠C?A) 60°
B) 70°
C) 90°
D) 120°

Answers

Answer: A) 60^(\circ)

Step-by-step explanation:

Given: ΔABC is similar to ΔDEF

Therefore,

∠A=∠D=50°

∠B=∠E=70°

∠C=∠F

Using Angle sum property, in triangle ABC, we get

\angle{A}+\angle{B}+\angle{C}=180^(\circ)\n\n\Rightarrow\ 50^(\circ)+70^(\circ)+\angle{C}=180^(\circ)\n\n\Rightarrow\ 120^(\circ)\angle{C}+=180^(\circ)\n\n\Rightarrow\ \angle{C}=180^(\circ)-120^(\circ)\n\n\Rightarrow\ \angle{C}=60^(\circ)

The angle sum property of a triangle says that, the sum of all the angles in a triangle is 180^(\circ).

Ok so if they are similar that means equal angles so 50+70=120 then 180-120=60 so the answer is A. #TeamAlvaxic

What is the vertex of the graph of the equation y= 3x^2+6x+1

Answers

y=a(x-h)^2+k \Rightarrow \hbox{vertex}=(h,k)\ny= 3x^2+6x+1\n y=3x^2+6x+3-2\n y=3(x^2+2x+1)-2\n y=3(x+1)^2-2\Rightarrow h=-1,k=-2\n\n (-1,-2)