Draw 2 shapes with a perimeter of 16 and an area of 12. Plz help!!!

Answers

Answer 1
Answer: a square with sides of 4 for perimeter and area of a rectangle with length 2 width 6
Answer 2
Answer: Hello,
1) a rectangle 2*6 :
==>
P=2*(2+6)=16    A=2*6=12

2)a triangle isocele base 6 height 4 :3²+4²=5²
==>
P: 6+5+5=16
A=4*6/2=12



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If x = - 2 and y = 3, what is the value of - x∧- y? the answer is 1/8. how? 

I need help with all of it

Answers

Domain = x values; Range = y values

1) Domain: [0,6] Range: [-3,3]

2) Domain: (-infinity, infinity) Range: [-1, infinity)

3) Domain: [-2, 5] Range: [-2, 1]

4) Domain: (-infinity, 4] Range: (-infinity, infinity)

5) Domain: [-3, 3] Range: [-4, 4]

6) Domain: (-infinity, 4] Range: (-infinity, infinity)

What is the length of the radius of a circle with a center at 2 + 3i and a point on the circle at 7 + 2i?

Answers

Hello,

A=2+3i
B=7+2i
AB=B-A=7+2i-(2+3i)=5-i

Radius=√(5²+1²)=√26

Answer:

b. squareroot 26

Step-by-step explanation:

What is 10,000,000 written as a power of ten?A.107
B. 108
C.10–8

D.10–7

Answers

A 10^7
(20 symbols too long for a test)

What is 20% off of £1.85? ^_^

Answers

p\%=(p)/(100)\n\n20\%=(20)/(100)=0.2\n\n20\%\ of\ \£1.85\ is\ 0.2\ *\ \£1.85=\£0.37
 £1.85 ________ 100 %
       x ________ 20 %

100x = 20 . 1,85
100x = 37
x = 37 / 100
x = 0,37

is 
 £0,37 ! 

What are the steps to solving the inequality 3b + 8 ≥ 14

Answers

Answer:

The solution of the given inequality 3b+8\geq 14 is: [2, \infty)

Step-by-step explanation:

Given the inequality equation: 3b+8\geq 14

Subtraction property of equality states that you subtract the same number to both sides of an equation.

Subtract 8 to both sides of an equation.

3b+8-8\geq 14-8

Simplify:

3b\geq 6

Division property of equality states that you divide the same number to both sides of an equation.

Divide both sides by 3 we get;

(3b)/(3) \geq (6)/(3)

Simplify:

b\geq 2

therefore, the solution of the given inequality  is: b\geq 2 or [2, \infty)

3b+8≥14
Subtract 8 from both sides
3b≥14-8
3b≥6
Divide both sides by 3
b≥6/3
b≥2

At a school supply store, binders cost $5 and pencil pouches cost $2. In one day, 42 of these items are sold for total sales of $144. Which system represents this (b represents binders and p represents pencil pouches), and how many binders were sold?

Answers

Answer:

Part 1) The system of equations that represent this situation is equal to

b+p=42  and 5b+2p=144

Part 2) 20 binders were sold

Step-by-step explanation:

Let

b -----> the number of binders sold

p -----> the number of pencil pouches sold

Part 1)

we know that

The system of equations that represent this situation is equal to

b+p=42

5b+2p=144

Part 2) How many binders were sold?

we have

b+p=42

p=42-b ------> equation A

5b+2p=144 -----> equation B

substitute equation A in equation B

5b+2(42-b)=144

5b+84-2b=144

3b=144-84

3b=60

b=20 binders