Algebra is not something I'm good at
algebra is not something I'm good at - 1

Answers

Answer 1
Answer: Hello,

slope=s=(5-8)/(9-3)=-3/6=-1/2


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A = v/t. Solve for t

Answers

   A = v/t     Multiply both sides by t
A(t) = v       Divide both sides by A
    t = v / A

Simplify a - {5b - [a - (3b - 2c) + c - (a - 2b -c. ]}.
-a - 6b + 4c
a - 6b + 4c
a - 10b + 4c
-a + 10b + 4c

Answers

♥B)a - 6b + 4c

♥First you need to d
istribute the Negative Sign.

=a+−1(5b(a−(3b2c)+c(a−2b−c)))

=a+−1(5b)+−1(−a)+−1(3b)+−1(2c)+−1(−c)+−1a+−1(2b)+−1(−c)

=a+5b+a+3b+2c+c+−a+2b+c

♥Now you need to 
Combine Like Terms:

=a+5b+a+3b+2c+c+−a+2b+c

=(a+a+−a)+(5b+3b+2b)+(2c+c+c)

=a+6b+4c

♥and you get your final answer: 
a−6b+4c

Answer: B

Step-by-step explanation:

Prove the diagonal connecting these vertex angles is perpendicular to the diagonal connecting the non-vertex angles

Answers

Seg BA is congr to seg BC and seg DA is cong to seg DC by given Seg BD is congr to seg BD by reflexive Tr. BAD is congr to tr. BCD by SSS

Need help with function

Answers

The answer is B, according to the Rules / Laws of Functions.
B is a function because it is the only one that has 4 different x values, therefore passing the vertical line test.

Each exterior angle of a regular polygon is 9°Calculate the number of sides of the polygon​

Answers

Answer:

40

Step-by-step explanation:

The sum of the exterior angles of a polygon = 360°

Divide this by the value of 1 exterior angle to find the number of sides n

n = 360 ÷ 9 = 40

Answer:

Required Answer:-

Let the number of sides=x

  • Each angle measures 9°

As we know that in a polygon

{\boxed{\sf Sum\;of\:exterior\:angles=360°}}

  • Substitute the values

{:}\longrightarrow\sf 9x=360

{:}\longrightarrow\sf x={\frac {360}{9}}

{:}\longrightarrow\sf x=40

\thereforeNumber of sides=40.

What are the zeros of j(x) in the polynomial equation?

Answers

Answer: x = (-3)/(2), 0,  (3)/(2)  

Step-by-step explanation:

     To find the zeros, we will find the solutions to this equation that make it equal 0. This is a cubic function, so we can assume that there will be three solutions.

Given:

  \displaystyle J(x) = (12x^3)/(5) -(27x)/(5)

Set the functionequal to 0:

  \displaystyle 0 = (12x^3)/(5) -(27x)/(5)

Subtract:

  \displaystyle 0 = (12x^3-27x)/(5)

Multiply both sides of the equation by 5:

  \displaystyle 0 = 12x^3-27x

Factor the polynomial:

  \displaystyle 0 = (3x)(2x-3)(2x+3)

Solve with the zero product property:

  0 = 3x        0 = 2x - 3        0 = 2x + 3

  0 = x          3 = 2x              -3 = 2x

  x = 0          x = (3)/(2)                  x = (-3)/(2)