MATHEMATICS MIDDLE SCHOOL

A Parking lot has a length of 100 yards wide and a length of 200 yards. The parking lot will be expanded by increasing both the length and the width by r yards. The area of the expanded lot will be twice the area of the original lot. Which equation can be used to find r?

Answers

Answer 1

Answer:

Answer:

40,000

Step-by-step explanation:

100x200=20,000

20,000x2=40,000

first we have to find the original are, then we know it gets doubled the size so we have to multiply that by 2, then we get 40,000.

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Gerardo says that a cube with edges measure 10 centimeters has a volume that is twice as much as a cube with sides that measure 5 centimeters. Explainand correct Gerardo's error.

Answers

V=LWH
cube
V=L^3
if it is doubled, then each dimention (LWH) is dobubled
since L=W=H
V=(2L)^3
V=8L^3
compared to orignal
L^3 vs 8L^3 it is 8 times more

demonstarte

10^3=1000
5^3=125
1000/125=8, not 2

The area of this rectangle is 165 sq meters the width is 22 meters what’s is the perimeter?

Answers

Answer:

59 meters

Step-by-step explanation:

A=L*W

165=L*22

L=165/22=7.5

7.5=L

P=L+L+W+W

7.5+7.5+22+22=59

Joe and Nate went for a walk . The system representing each boys progress is graphed below. Which statements about the system and scenario are true?

Answers

Answer:

A,D,E

Step-by-step explanation:

I took the test

Answer:

there is not enough information

The original price of a skateboard is $50. The sale price includes a 20% discount. What is the sale price

Answers

50 × 0.8 = $40 is the sale price

What is 50 sub by 20?
Well, your answer would be 10.

It wont add up but this is your answer
10
.........................................................
Hope this helped! Have a nice day.

Verify cot x sec^4x=cotx +2tanx +tan^3x

Answers

Answer:

See explanation

Step-by-step explanation:

We want to verify that:

$\cot(x) \: { \sec}^(4) x = \cot(x) + 2 \tan(x) + { \tan}^(3) x$

Verifying from left, we have

$\cot(x) \: { \sec}^(4) x = \cot(x) \: ( 1 + { \tan}^(2) x )^(2)$

Expand the perfect square in the right:

$\cot(x) \: { \sec}^(4) x = \cot(x) \: ( 1 + { 2\tan}^(2) x + { \tan}^(4) x)$

We expand to get:

$\cot(x) \: { \sec}^(4) x = \cot(x) \: + \cot(x){ 2\tan}^(2) x +\cot(x) { \tan}^(4) x$

We simplify to get:

$\cot(x) \: { \sec}^(4) x = \cot(x) \: + 2 ( \cos(x) )/(\sin(x) ) ) * \frac{{ \sin}^(2) x}{{ \cos}^(2) x} +( \cos(x) )/(\sin(x) ) ) * \frac{{ \sin}^(4) x}{{ \cos}^(4) x}$

Cancel common factors:

$\cot(x) \: { \sec}^(4) x = \cot(x) \: + 2 \frac{{ \sin}x}{{ \cos}x} +\frac{{ \sin}^(3) x}{{ \cos}^(3) x}$

This finally gives:

$\cot(x) \: { \sec}^(4) x = \cot(x) + 2 \tan(x) + { \tan}^(3) x$

Victor went to the barber to get a haircut. The haircut cost $9. Victor gave the barber a 25% tip. How much did Victor spend at the barber shop altogether?