In the United States, volume of irrigation water is usually expressed in acre-feet. One acre-foot is a volume of water sufficient to cover 1 acre of land to a depth of 1 ft (640 acres = 1 mi2, 1 mi = 5280 ft). The principal lake in the California Water Project is Lake Oroville, whose water storage capacity is listed as 3.54 x 106 acre-feet. Express the volume of Lake Oroville in (a) cubic feet, (b) cubic meters, and (c) US gallons.

Answer:

pH after the addition of 10 ml NaOH = 4.81

pH after the addition of 20.1 ml NaOH = 8.76

pH after the addition of 25 ml NaOH = 8.78

Explanation:

(1)

Moles of butanoic acid initially present = 0.1 x 20 = 2 m moles  = 2 x 10⁻³ moles,

Moles of NaOH added = 10 x 0.1 = 1 x 10⁻³ moles

                          CH₃CH₂CH₂COOH + NaOH ⇄ CH₃CH₂CH₂COONa + H₂O

Initial conc.            2 x 10⁻³                 1 x 10⁻³           0            

Equilibrium             1 x 10⁻³                   0                  1 x 10⁻³

Final volume = 20 + 10 = 30 ml = 0.03 lit

So final concentration of Acid =

Final concentration of conjugate base [CH₃CH₂CH₂COONa]

Since a buffer solution is formed which contains the weak butanoic acid and conjugate base of that acid .

Using Henderson Hasselbalch equation to find the pH

Final answer:

During titration of butanoic acid with NaOH, we can calculate the pH at various points using the Henderson-Hasselbalch equation for buffer scenarios. After 10.00mL of NaOH, the pH will be 4.74. After 20.10 mL, the pH will be 8.27, and after 25.00 mL, the pH will be 12.30.

Explanation:

This involves calculating the pH at various stages during a titration procedure. Here the titration involves a weak acid, butanoic acid, with a strong base, NaOH. We can simplify the reaction as follows: CH₃CH₂CH₂COOH + OH- --> CH₃CH₂CH₂COO- + H₂O.

(a) After 10.00 mL of NaOH is added, the system isn't at equivalence. Here, the reaction hasn't fully completed and a buffer solution is present. Using the Henderson-Hasselbalch equation, we can find the pH: pH = pKa + log([base]/[acid]). After calculating, we can find pH = 4.74.

(b) After 20.10 mL NaOH is added, the system reaches past equivalence. The pH can be determined by finding pOH using the remaining OH- concentration and then subtracting from 14. After the calculation, the pH = 8.27.

(c) For 25.00 mL of NaOH, the system is beyond equivalence and extra OH- ions increase pH. The pH calculation is like previous step and the result will be pH = 12.30.

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Answer:

Explanation:

BrCl₃ is an interhalogen compound with a hybridization of sp³d. The approximate bond angles can be predicted from the structure (attached below). Although, the lewis structure might be predicted to be trigonal bipyramidal from the structure, it is however a T-shaped geometry because of it's two lone pairs.

Also, from the structure attached, it can be predicted that the approximate bond angles about the central atom is 120° (360 ÷ 3) since each of the three chlorine atoms is equally spaced about the central atom.

The Lewis structure for BrCl₃ is attached to the image below. The bond angles around the central atom, bromine (Br), are 90 degrees between the bromine and each chlorine atom. Therefore, option B is correct.

A Lewis structure, also known as an electron-dot structure or Lewis dot structure is a diagram that represents the valence electrons of an atom or molecule.

Bromine (Br) is in Group 7A and has 7 valence electrons, while each chlorine (Cl) atom in Group 7A also has 7 valence electrons.

Br: 1 atom × 7 valence electrons = 7 valence electrons

Cl: 3 atoms × 7 valence electrons = 21 valence electrons

Total valence electrons = 7 + 21 = 28

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The specie which is acting as a catalyst is; Ag+(aq).

Discussion:

The catalyst is a specie that exists in the same form at the beginning and end of the reaction.

The reaction's mechanism is as follows;

• Step 1: Ag+(aq) + Ce⁴+(aq) <-----> Ag²+(aq) + Ce³+(aq)

• Step 2: Tl+(aq) + Ag²+(aq) -----> Tl²+(aq) + Ag+(aq)

• Step 3: Tl²+(aq) + Ce⁴+(aq) -----> Tl³+(aq) + Ce³+(aq)

Evidently, although Ag+(aq) was converted to Ag²+(aq) in Step 1 of the reaction; the Ag²+(aq) is reverted back to Ag+(aq) in Step 2 of the reaction.

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Answer:

Ag⁺ acts as the catalyst.

Explanation:

Hello,

In this case, each step is reorganized:

- Step 1:

- Step 2:

- Step 3:

In such a way, Ag⁺ is converted to Ag²⁺ in the first step, but then it is regenerated to simple Ag⁺, therefore, Ag⁺ acts as the catalyst.

Best regards.

Answer:

I belive the answer is A but the image quality is hard to tell.

Explanation:

As pressure increases the higher the melting point of rock becomes making it harder to melt, thats why molten rocks brought to the surface melt because of the change in pressure.  

The Bunsen burner is a heating apparatus used to heat samples in the laboratory. The correct answer is option B: )Leave the gas stop open for a few minutes before lighting to clear the line.

A Bunsen burner is commonly used as a heating apparatus. It contains a gas that can be controlled using a gas regulator.

It is necessary to do the following before lighting the Bunsen burner;

• Make sure there are no holes in the hose connected to the burner.
• Clear the burner area of flammable materials such as solvents and papers.
• Check that the gas regulator and air inlet on the burner can be adjusted.

So, it is not necessary to Leave the gas stop open for a few minutes before lighting to clear the line before lighting a Bunsen burner.

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Answer:

the answer is opetuon B