MATHEMATICS HIGH SCHOOL

Check my answer please? If p varies directly with q, and p = 8 when q = 2, what is the value of p when q = 7?

A.
p = 40

B.
p = 100

C.
p = 28

D.
p = 1

i think that it's c.

Answers

Answer 1
Answer: yes you are right it's C

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colby and jaquan are growing bacteria in an experiment in a laboratory. Colby starts with 50 bacteria in his culture and the number of bacteria doubles every two hours. Jaquan has a different type of bacteria that doubles every three hours. How many bacteria should Jaquan start with so that they have they have the same amount at the end of the day?
The vertex of this parabola is at (-3, 6). Which of the following could be its equation? A. y = -3(x + 3)2 + 6 B. y = -3(x + 3)2 - 6 C. y = -3(x - 3)2 + 6 D. y = -3(x - 3)2 - 6

Can you explain 3x+4/5=7/10. Solve

Answers

3x+ (4)/(5)= (7)/(10)\ \ | -(4)/(5)\n \n3x+ (4)/(5) -(4)/(5)= (7)/(10)-(4)/(5)\n \n3x = (7)/(10)-(8)/(10) \n \n3x = -(1)/(10) \ \ /*(1)/(3)\n \nx=-(1)/(30)



or \n \n (3x+ 4)/(5)= (7)/(10) \ \ /*10 \n \n 2(3x+4)=7\n \n6x+8 = 7\ \ |-8

6x+8-8=7-8\n \n6x=-1\ \ /:6 \n \n x=-(1)/(6)
3x+ (4)/(5)= (7)/(10) \n \n3x= (7)/(10)-(4)/(5)\n \n3x=(7)/(10)-(8)/(10)\n \n3x=- (1)/(10) \ /:3\n \nx=-(1)/(10)\cdot (1)/(3)\n \nx=-(1)/(30)

-------------------------------------------------

(3x+4)/(5) = (7)/(10) \n \n10(3x+4)=5\cdot 7\n \n30x+40=35\n \n30x=35-40\n \n30x=-5\ /:30\n \nx=- (5)/(30) \n \nx=-(1)/(6)

For which pairs of functions is (f circle g) (x)?f (x) = x squared and g (x) = StartFraction 1 Over x EndFraction
f (x) = StartFraction 2 Over x EndFraction and g (x) = StartFraction 2 Over x EndFraction
f (x) = StartFraction x minus 2 Over 3 EndFraction and g (x) = 2 minus 3 x
f (x) = one-half x minus 2 and g (x) = one-half x + 2

Answers

Ok so I think the fraction is 2-241x because I did this before

Answer:

2-241x

Step-by-step explanation:

**WILL GIVE MEDAL!!!**A car traveling on a highway is 60 miles away from home after 1 hour, and is 300 miles away from home after 5 hours. What is the rate of change of the car’s distance over time?

a. 1/60 mph
b. 15/2 mph
c. 55mph
d. 60 mph

Answers

If the car is traveling 60mph and is 300 miles away after 5 hours, the rate of change here is to divide 5 by 300. The answer is 60 (D). The problem here would look like 300/5=60. So the rate of change of the car's distance over time would be 60.

I'm not really good at clearing fractions I need help with this problem please!

Answers

1/4x + 3 = 2x - 5/8

Find least common multiplier of 4x,8 is  8x

Multiply by LCM = 8x

1/4 x * 8 x + 3 * 8 x = 2 x * 8 x - 5/8 * 8 x

Refine:

2 + 24 = 16 x² - 5 x

Subtract 16 x² - 5 x from both sides:

2 + 24 x - ( 16 x² -5 x) = 16 x² - 5 x - (16 x²-5 x)

Refine: - 16 x² - 29 x + 2 = 0

Solving with the quadratic formula :

for a = - 16 , b = 29 and c = 2

x1 = - 29 √ 29² - 4(-16)*2
        -----------------------------
              2 (-16)

x1 = - √ 969  - 29
      ---------------------
                32


x2 = - 29 - √ 29² -4(-16)*2
        -----------------------------
               2(-16)

x2 = √ 969  + 29
      ---------------------
                32

The final solutions to the quadratic equation are:


x1 = - √ 969 - 29
      -------------------
              32

x2 = √ 969 + 29
      -------------------
             32


hope this helps!

Computer usage has increased over time. But has the increase been more linear or more exponential? In 1997, 22.2% of the population over three years of age, or about 60 million people, used the internet. In 1998, 32.7% of the population over three years of age, or about 90 million people, used the internet. a. If the usage increased linearly, write the linear function that would give 60 million people in year 0 and 90 million in year 1.

Answers

That's an increase of 30,000,000 people in one year, a slope of 30 million and a good year for the internet.

If t is the year, and p is number of internet users,

p = 30000000(t - 1997) + 60000000

Answer: p = 30000000(t - 1997) + 60000000

As for linear versus exponential, one year of data can't really distinguish.

The amount of money left on a loan that Kira owes her grandmothers is represented by the function k(t)=280(.88)^t where k(t) represents the amount of money left on a the loan and t represents the time, in years. Find r, the percent change and explain what it represents.

Answers

Given:
k(t) = 280(0.88)^t

t = 1 ; t = 2 ; t = 3 
k(1) = 280(0.88)¹ = 280(0.88) = 246.40
k(2) = 280(0.88)² = 280(0.7744) = 216.83
k(3) = 280(0.88)³ = 280(0.681472) = 190.81

280 - 246.40 = 33.60 ⇒ 33.60/280 = 0.12
246.40 - 216.83 = 29.57 ⇒ 29.57/246.40 = 0.12
216.83 - 190.81 = 26.20 ⇒ 26.20/216.83 = 0.12

The rate is 0.12 or 12%
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