Water pipes can burst during very cold winters due to a phenomenon known as "freeze-thaw cycle." When temperatures plummet, water inside the pipes can freeze, causing it to expand and exert pressure on the pipe walls.
Water molecules expand as they freeze, creating a buildup of pressure within the pipe. Pipes are designed to withstand a certain amount of pressure, but when it exceeds their capacity, they can rupture or burst. Furthermore, pipes made of materials like metal or plastic can become brittle in extremely cold temperatures. The cold causes the material to contract, reducing its flexibility and making it more susceptible to cracks and breaks. This can weaken the structural integrity of the pipe, making it more likely to rupture when subjected to the internal pressure from the frozen water. Preventing pipe bursts during cold winters involves insulating pipes, maintaining a constant flow of water, and keeping indoor spaces adequately heated to mitigate the freezing and expansion of water within the pipes.
Additionally, stagnant water in pipes is more prone to freezing than flowing water. Pipes that aren't used frequently, like those in less-used areas of a building, may freeze more easily during extended cold periods.
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Answer: Here's my answer, I made it step-by-step so you can understand it! <3
Explanation:
To find the centripetal acceleration of the tip of the fan blade, we can use the formula for centripetal acceleration:
a = (v^2) / r
where:
a is the centripetal acceleration,
v is the linear velocity, and
r is the radius of the circular path.
Given that the fan completes 2 rotations every 1.0 second, we can find the angular velocity (ω) using the formula:
ω = (2π * n) / t
where:
ω is the angular velocity,
π is a constant (approximately 3.14),
n is the number of rotations (2),
and t is the time taken (1.0 second).
Substituting the values into the formula, we have:
ω = (2π * 2) / 1.0 = 4π rad/s
Next, we can calculate the linear velocity (v) using the formula:
v = r * ω
Substituting the given radius value (0.61 m) and the angular velocity we found earlier, we have:
v = 0.61 * 4π = 2.44π m/s
Finally, we can calculate the centripetal acceleration (a) using the formula:
a = (v^2) / r
Substituting the linear velocity and the radius, we have:
a = (2.44π)^2 / 0.61 = 5.88π^2 / 0.61 ≈ 96 m/s²
Therefore, the centripetal acceleration of the tip of the fan blade is approximately 96 m/s² (Option 4).
The speed are they moving at will be 0.5 m/sec.Law of conservation of momentum is applied.
According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.
The given data in the problem is;
(m₁) is the mass of 1st gilder= 0.40 kg
(u₁) is the initial velocity = 2 m/s
(m₂) is the mass of 2nd gilder = 1.20 kg
(u₂) is the initial velocity of 2nd gilder = 0 m/s
(v) is the velocity after collision =.?
According to the law of conservation of momentum;
Momentum before collision =Momentum after collision
Hence, the speed are they moving at will be 0.5 m/sec
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Answer:
3.43 kPa
Explanation:
Pressure is defined as the ratio between the force applied and the area of the surface on which the force is applied:
in this problem, the force corresponds to the weight of the load, which is given by the product between its mass (350 kg) and the acceleration due to gravity (9.8 m/s^2):
And since the area on which this force is applied is , the pressure exerted on the upper surface of the liquid is
Answer:
maria is right.
Explanation: