Is newton third law accurate for electric forces?

Answers

Answer 1

Answer:

An object with greater charge will exert a greater force on an object than an object with smaller charge would. However, if you consider two charges that exert a force on each other, regardless of the magnitude of charge, both charges will exert an equal force on each other because of Newton's third law.

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The ball was kicked in the air and it iss about to hit the . if horizonta componenet of its final velocity is 10m/s and vertical component of its final velocity is -10m/s .what is the magnotide of th final vellocity of the ball?

The bob of a pendulum has 600 J of kinetic energy at the bottom of its swing. As the bob rises to a height of 4 m above the bottom, it gains 400 J of potential energy. How much kinetic energy does it have at this point?200 J

300 J

400 J

1000 J

Answers

Answer:

The K.E of the pendulum is, K.E = 200 J

Explanation:

Given data,

The kinetic energy of the bob of the pendulum at the bottom, K.E = 600 J

The potential energy at the height 4 m, P.E = 400 J

According to the conservation of energy, the total energy of the mechanical system should be conserved.

At the bottom of the swing, the entire mechanical energy of the pendulum is purely kinetic. Therefore the total energy

E = P.E + K.E

= 0 + 600 J

= 600 J

Therefore, the total energy of the system, E = 600 J

At height 4 m, the total energy of the system remains the same.

Therefore,

600 J = 400 J + K.E

K. E = 600 J - 400 J

= 200 J

Hence, the K.E of the pendulum is, K.E = 200 J

A ball is thrown horizontally from the top of a building 0.10 km high. The ball strikes the ground at a point 65 m horizontally away from and below the point of release. What is the speed of the ball just before it strikes the ground?

Answers

The speed of the ball just before it strikes the ground is equal to 46.55 m/s.

Given the following data:

Horizontal distance = 65 meters

Height of building = 0.10 km = 100 meters

We know that the acceleration due to gravity (g) of an object on planet Earth is equal to 9.8 $m/s^2$ .

To determine the speed of the ball just before it strikes the ground:

First of all, we would determine the time it took the ball to strike the ground by using the formula for maximum height.

$H = (1)/(2) gt^2\n\n100 = (1)/(2) * 9.8 * t^2\n\n200 = 9.8t^2\n\nt^2 = (200)/(9.8) \n\nt^2=20.41\n\nt=√(20.41)$

Time, t = 4.52 seconds

Next, we would find the horizontal velocity:

$Horizontal\;velocity = (horizontal\;distance)/(time) \n\nHorizontal\;velocity = (65)/(4.52)$

Horizontal velocity, V1 = 14.38 m/s

Also, we would find the velocity of the ball in the horizontal direction:

$V_2^2 = U^2 + 2aS\n\nV_2^2 = 0^2 + 2(9.8)(100)\n\nV_2^2 = 1960\n\nV_2 = √(1960) \n\nV_2 = 44.27 \;m/s$

Now, we would calculate the speed of the ball just before it strikes the ground by finding the resultant speed:

$V = √(V_1^2 + V_2^2) \n\nV = √(14.38^2 + 44.27^2)\n\nV = √(206.7844‬ + 1959.8329‬)\n\nV =√(2166.6173)$

Speed, V = 46.55 m/s

Answer:

v = 46.55 m/s

Explanation:

It is given that,

A ball is thrown horizontally from the top of a building 0.10 km high, d = 0.1 km = 100 m

The ball strikes the ground at a point 65 m horizontally away from and below the point of release, h = 65 m

At maximum height, velocity of the ball is 0. So, using the equation of motion as :

$d=ut+(1)/(2)at^2$

Here, a = g

$100=0+(1)/(2)* 9.8t^2$

$t=4.51\ s$

Let $v_x$ is the horizontal velocity of the ball. It is calculated as :

$v_x=(65\ m)/(4.51\ s)=14.41\ m/s$

Let $v_y$ is the final speed of the ball in y direction. It can be calculated as :

$v_y^2+u_y^2=2as$

$u_y=0$

$v_y^2=2gd$

$v_y^2=2* 9.8* 100$

$v_y=44.27\ m/s$

Let v is the speed of the ball just before it strikes the ground. It is given by :

$v=√(v_x^2+v_y^2)$

$v=√(14.41^2+44.27^2)$

v = 46.55 m/s

So, the speed of the ball just before it strikes the ground is 46.55 m/s. Hence, this is the required solution.

What happens to light when it enters a lens? A. It speeds up.

B. It is reflected.

C. It is refracted.

D. It becomes brighter.

Answers

Good Morning! When the light passes through a lens - whether of increase or withdrawal - it tends to be refracted, that is, to suffer a deviation in its trajectory. Depending on the type of lens, it may be that some of the light is reflected too, but this is not the common parameter. Correct letter is therefore c). Hugs!Hope this helps. Let me know if you need additional help!

Answer: i think the answer is c hope this helps

When evaporation occurs in a dish of water, the molecules left behind in the water: a) Are larger in size. b) Are more concentrated. c) Are less dense. d) Are transformed into gas.

Answers

Answer:

b) Are more concentrated.

Explanation:

Audition begins when sound waves strike the ________,causing it to vibrate. A) eardrum B) anvil C) stirrup D) cochlea

Answers

Answer: A) eardrum

Explanation: Audition refers to the sense of hearing. It is the process by which sound waves are perceived and interpreted by our brain. When sound waves enter the ear, they cause the eardrum to vibrate. These vibrations then travel further into the inner ear, leading to a chain of events that ultimately allows us to interpret and understand the sounds that we hear. Therefore, A is correct.

That's it!

Interacting with others while exercising is beneficial to social health because it allows a person to __________.

Answers

feel better and develop communication skills

It's not only the physical well-being that has developed as well as intellectual and emotional aspect of an individual. When having conversation to someone and you are doing something it's also the same of having a multitask work. That all senses response quickly and something is developing in you, at same time you are establishing good rapport towards others.

Answer:

develop better communication skills

Explanation:

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