Answer:
Step-by-step explanation:
if he can walk 0.5 miles in 6 minutes at a constant rate then you can say that he can walk 1 mile in 12 minutes.
therefore he can walk 1/12 mile ever one minute
so m=1/12t
To find the equation of a line tangent to the given curve, we need to find the derivative of the curve at the point of tangency and substitute the x-coordinate of the point of tangency to find the slope. The equation of the tangent line with 0 slope and y-intercept of 8 is y = 8.
To find the equation of a line tangent to a curve, we need to find the derivative of the curve at the point of tangency.
The given curve is y = 4x² + 1 (equation 1).
First, find the derivative of equation 1, which gives us dy/dx = 8x (equation 2).
Next, substitute the x-coordinate of the point of tangency into equation 2 to find the slope of the tangent line.
Since the line cuts the y-axis at (0,8), the x-coordinate of the point of tangency is 0.
Substituting x=0 into equation 2, we get the slope of the tangent line as m = 8(0) = 0.
The equation of a line in the form y = mx + c, where m is the slope and c is the y-intercept.
Since the slope of the tangent line is 0, the equation of the tangent line is y = 0x + c. And since the line cuts the y-axis at (0,8), the y-intercept is 8.
Therefore, the equation of the tangent line is y = 8.
#SPJ3
A generic point on the graph of the curve has coordinates
The derivative gives us the slope of the tangent line at a given point:
Let k be a generic x-coordinate. The tangent line to the curve at this point will pass through and have slope
So, we can write its equation using the point-slope formula: a line with slope m passing through has equation
In this case, and , so the equation becomes
We can rewrite the equation as follows:
We know that this function must give 0 when evaluated at x=0:
This equation has no real solution, so the problem looks impossible.
Answer:2/15
Step-by-step explanation:
A. 144 sq. in.
B. 154 sq. in.
C. 162 sq. in.
D. 190 sq. in.