Endpoints of major axis at (0,6) and (0,-6) endpoints of minor axis at (-3,0) and (3,0)

Answers

Answer 1
Answer: we can see that the center is (0,0)

and from commments we know tat it is ellipse

since major axis is y direction ( and center (0,0)), it is a vertical ellipse
in form
(x^(2))/(b^(2)) + (y^(2))/(a^(2)) =1

where a is the distance from the center to major axis end
b is distance of minor axis
and a>b always for ellipse

from (0,0) to (0,6) is 6 units, major axis
from (0,0) to (3,0) is 3 units, minor axis

(x^(2))/(3^(2)) + (y^(2))/(6^(2)) =1


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A taxi service charges an inital fee of $3 plus $1.80 per mile.how far can you travel on $12

Answers

1.80x + 3 = 12

isolate the x

1.80x + 3 (-3) = 12 (-3)

1.80x = 9

1.80x/1.80 = 9/1.80

x = 9/1.80

x = 5

you can travel up to 5 miles

hope this helps
m= # of miles

$12 < $3 + $1.80m
subtract 3 from both sides
9 < 1.80m
divide both sides by 1.80
5 < m

ANSWER: They can travel 5 miles on $12.

Hope this helps! :)

The area of a square with sides of 2 feet is 4 square feet. The area of a square with sides of 4 feet is 16 square feet. what equation fits this data?Choices

y=4x
or
y=x+2
or
y=x squared
or
y=2x

Answers

A square, by definition, is an equilateral quadrilateral. It has already been established that the formula for the area of a square is to take the square of the length of its one side. To prove this,

A = 2^2 = 4
A = 4^2 = 16

Thus, the equation is y = x squared

3. What is the algebraic expression for the following word phrase: the quotient of x and 2y?

Answers

Answer:

x/2y

Step-by-step explanation:

quotient-division

A negative number raised to an odd power is _____ negative. a)always
b)sometimes
c)never

Answers

A negative number raised to an odd power is always negative. The correct answer is A, always. 

A single die is rolled twice. Find the probability of rolling an Odd number the first time and a number greater than 4 the second time.

Answers

The probability of rolling an  odd number the first time and a number greater than 4 the second time is 1/6

The sample space of a single die is

\mathbf{S = \{1,2,3,4,5,6\}}

So, the total sample is 6

The odd numbers are

\mathbf{Odd = \{1,3,5\}} --- 3 odd numbers.

So, the probability of selecting an odd number is:

\mathbf{P(Odd) = \frac 36}

Simplify

\mathbf{P(Odd) = \frac 12}

The numbers greater than 4 are

\mathbf{Greater = \{5,6\}} --- 2 numbers greater than 4.

So, the probability of selecting a number greater than 4 is:

\mathbf{P(Greater) = \frac 26}

Simplify

\mathbf{P(Greater) = \frac 13}

The probability of rolling an  odd number the first time and a number greater than 4 the second time is calculated as follows:

\mathbf{P = P(Odd) * P(Greater)}

So, we have:

\mathbf{P = \frac 12 * \frac 13}

\mathbf{P = \frac 16}

Hence, the probability is 1/6

Read more about probabilities at:

brainly.com/question/11234923

Answer: 1/6

Step-by-step explanation:

A die has 6 numbers which are 1, 2, 3, 4, 5 and 6.

Odd numbers in a die = 1, 3 and 6

Numbers greater than 4 = 5 and 6

Probability of rolling an odd number = 3/6 = 1/2

Probability of rolling a number greater than 4 = 2/6 = 1/3

We then multiply both values gotten. This will be:

= 1/2 × 1/3

= 1/6

Therefore, the probability of rolling an odd number the first time and a number greater than 4 the second time is 1/6.

A plane, parallel to the base of a cone intersects the cone at the midpoint between points A and B. Determine the area of the cross-section formed by the intersection of the plane and the cone. Leave your answer in terms of pi. 2o height 6 radiusA) 1.5π in2
Eliminate
B) 3π in2
C) 9π in2
D) 36π in2

Answers

Answer:

Area of cross-section is9\pi in^(2)

Step-by-step explanation:

Given a cone and a plane parallel to base intersect the cone at the mid point of points between A and B.

We have to find the area of cross-section formed by intersection of the plane and the cone which is a new circle formed.

Given,   height=20 in

             radius=6 in

By mid point theorem i.e the line segment formed by joining the mid points of two side of triangle is parallel to third equal to half of the third side.

therefore new circle formed is of radius 3 in

Hence, area of cross-section formed by intersection of the plane and the cone which is a new circle formed= \pir^(2)

                                                        = 3^(2)\pi

                                                        =9\piin^(2)