You can find water stored as a gas in the atmosphere.
You can find water stored as a solid in the Glaciers.
For PLATO Users
The Cycle And Movements Of Water Link Below
Answer:
K < Fe < Br < Kr
Explanation:
Given chemical elements;
Potassium
Iron
Bromine
Krypton
Problem; arrange in order of increasing electronegativity
Solution:
The electronegativity of an element measures the relative tendency with which the atoms of the element attracts valence electrons in the chemical bond.
To solve this problem, we are going to use values of electronegativity from the Pauling's electronegativity table of elements;
For;
Potassium = 0.8
Iron = 1.83
Bromine = 2.8
Krypton = 3.0
So;
K < Fe < Br < Kr
35.2 grams of oxygen are required to react with 10.0 grams of octane
Complete combustion of Hydrocarbons with Oxygen will be obtained by CO₂ and H₂O compounds.
If O₂ is insufficient there will be incomplete combustion produced by CO and H and O
Hydrocarbon combustion reactions (specifically alkanes)
For gas combustion reaction which is a reaction of hydrocarbons with oxygen produces CO₂ and H₂O (water vapor). can use steps:
Balancing C atoms, H and last atoms O atoms
Octane combustion reaction
C₈H₁₈ + O₂ ---> CO₂ + H₂O
To equalize the reaction equation we give the reaction coefficients with variables a, b and c while the most complex compounds, namely Octane, we give the number 1
So the reaction becomes
C₈H₁₈ + aO₂ ---> bCO₂ + cH₂O
C atom on the left 8, right b, so b = 8
left H atom = 18, right 2c so 2c = 18 ---> c = 9
Atom O on the left 2a, right 2b + 2c, so 2a = 2b + 2c
2a = 2.8 + 9
2a = 16 + 9
2a = 25
a = 25/2
The equation becomes:
C₈H₁₈ + 25/2O₂ ---> 8CO₂ + 9H₂O or be
2C₈H₁₈ + 25O₂ ---> 16CO₂ + 18H₂O
To find the mass O2, we find the mole first from the mole ratio with Octane
Mr. octane = 8.Ar C + 18.Ar H
Mr. octane = 8.12 + 18.1
Mr octane = 96 + 18
Mr octane = 114
known octane mass: 10 grams then the mole:
mol = gram / Mr
mol = 10/ 114
mol = 0.088
because of the ratio of the reaction coefficient between O2 and octane = 25: 2 then the mole of O₂ =
25/2 x 0.088 = 1,1
So that the mass O₂ =
mole. Mr = 1.1 32
mass = 35.2 grams
a combustion reaction
the type of chemical reaction
The combustion of alkanes, alkenes, and alkynes
Complete combustion of a sample of a hydrocarbon
Keywords: Complete combustion of Hydrocarbons, alkanes, equalize the reaction equation
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