leon deposited $30,000 in a bank which paid 2% interest per year. after 1 year, leon withdraw all his money including the interest. How much money did leon withdraw in all?
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Related Questions
Bruce traveled 15 kilometers in 60 minutes.Which ratio accurately shows how many minutes it took Bruce to travel one kilometer?
Solve the equation 5(-4a+8)-5(6a-5)=15
To find the percent for 16 does it increase or decrease?
Is 2750 a reasonable answer for 917 x 33?
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slope=(y2-y1)/(x2-x1)
(0,6) and (5,-4)
x1=0
y1=6
x2=5
y2=-4
slope=(-4-6)/(5-0)=-10/5=-2
slope=-2
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I looked at this just before going to bed, and it ruined my night, worrying
about it. Then, this morning, when I actually set pencil to paper, it turned
out not to be such a vicious limbic twister.
You DO need to know how to take a chain derivative, though. I must say,
I'm surprised to see this much Calculus at the middle school level. Maybe
it's MY problem, but I just can't see a way to do it without this derivative,
so I'll just show you how I did it:
The ants begin together, and crawl out along the legs of a right triangle.
-- The first one moves at 4 ft/min, so after 't' minutes, he's 4t-ft from
the vertex. The question concerns what happens when this one has
covered 12-ft. That will happen in (12/4) = 3 minutes after he starts out.
-- The second one starts out 2-min later, and moves at 5-ft/min. So,
after 't' minutes, he's 5(t-2) ft from the vertex.
-- The distance between them is the hypotenuse of the right triangle.
The square of the distance is the sum of the squares of the legs:
D² = (4t)² + [ 5(t-2) ]²
We're actually going to need to know how far apart they are after 3 minutes,
so let's do that now.
D² = (4 x 3)² + (5 x 1)² = (12)² + (5)² = 144 + 25 = 169
D = √169 = 13-ft apart, after the first guy has covered 12 feet.
We will need this shortly.
OK. Now, let's simplify the equation for the distance between them,
(as we get ready to differentiate it).
D² = (4t)² + [ 5(t-2) ]²
D² = 16t² + (25) (t² - 4t + 4)
D² = 16t² + 25t² - 100t + 100
D² = 41t² - 100t + 100
The question asks "How fast is the distance between them changing . . . ? ",
and we know that this is the derivative of 'D' with respect to 't' . It's easy to
take the derivative of the right side of the equation, but what about the derivative
of ' D² ' ? That's the part that I'm not so sure about in middle school, so I'll just
give it to you:
(Derivative of D²) is [ (2D) times (derivative of D) ] .
Now we can take the derivative of each side of the equation:
(2D) x (derivative of D) = 82 t - 100 .
derivative of D = (82 t - 100) / (2D)
That's how fast the distance between them is changing at any time 't' .
After 3 minutes, we calculated 'D' earlier. It's 13-ft
derivative of D = [ (82 x 3) - 100 ] / (2 x 13)
= 146 / 26
= 5.615 feet per second.
Are you confident ? Do you trust me?
I'm not confident at all, and I don't trust myself.
The best I can suggest is for you to go through this and look for my mistakes,
or better yet, sit down with your teacher and go through it for mistakes.
That'll help you think about it and understand it, even if my work is wrong.
What you have to know is that:
Also:
t=time snapshot (in minutes)
x=distance first ant has travelled
y=distance second ant has travelled (perpendicular to the first ant)
D=distance between both ants
--------------------------------------
Now, when:
t=0, x=0, y=0, D=0
t=1, x=4, y=0, D=4
t=2, x=8, y=0, D=8
t=3, x=12, y=5, D=13
Now we quantize time and find the tangent line (slope) between two points on the distance vs time graph at t=3 and t=3.000001, knowing that distance is represented by feet and time is represented in minutes.
When t=3.000001, x=12.000004, y=5.000005 D=13.00000562...
Now we find the slope on the distance vs time graph between the points (3,13) and (3.000001, 13.00000562).
So, at the point (3,13) on the distance vs time graph, the two ants are moving away from each other at approximately 5.62 feet per minute.
Notations you may require to understand problem in the attachment below.
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Final answer:
Given 4 consecutive odd numbers with a sum of 224, we can create an equation to solve for the first number (x). After calculating x = 53, we find the largest number to be 59.
Explanation:
This is a problem about consecutive odd integers, which are odd integers that follow each other successively. Let's denote the first odd integer as x, the second as x+2, the third as x+4, and the fourth as x+6. These are all odd because adding 2 to an odd number always results in the next odd number.
The question states that the sum of these four consecutive odd numbers is 224, so we can create the following equation: x + (x+2) + (x+4) + (x+6) = 224.
Simplify this equation to obtain 4x + 12 = 224. Then, solve for x by first subtracting 12 from both sides to get 4x = 212 and then dividing by 4 to get x = 53. Our highest odd number would be x+6 which equals 59.
Learn more about Odd Integers here:
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Final answer:
The four consecutive odd integers whose sum is 224 are 53, 55, 57, and 59. The largest of these integers is 59.
Explanation:
To find four constructive odd integers whose sum is 224, you first need to understand that consecutive odd integers follow a certain sequence, each increasing by 2 from the previous one. Let's label the first consecutive odd integer as 'n'. So, the four consecutive numbers will be: n, n + 2, n + 4, n + 6.
According to the problem, the sum of these four numbers equals 224:
n + (n+2) + (n+4) + (n+6) = 224.
Solve this equation to find the value of 'n'. You'll get n = 52. Hence, the numbers are 52, 54, 56, 58.
Since we are looking for odd numbers, let's start with 53 (the first odd number greater than 52) and proceed: 53, 55, 57, 59. And these four numbers do sum up to 224. Therefore, the largest number in this series is 59, our final answer.
Learn more about Consecutive Odd Integers here:
#SPJ12
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13x-16=-208 negative 208(-208)
-12--208=196
Cube with sides of four millimeters
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a=6*a^2
a= 6*16=96mm^2