(y-3)²=4y-12
First we need to start by subtract 4y-12 from both sides
y²-6y+9-(4y-12)= 4y-12-(4y-12)
y²-10y+21=0
Now we need to do the factorization of the equation
we gonna factor the left side of it
(y-3)(y-7)=0
Set factors equal to 0
y-3=0 or y-7=0
y=3 or y=7
I hope that's help :0
Answer:
Rectangle shaped cross section is formed by intersection of plane and prism.
Step-by-step explanation:
Given: A rectangular Prism.
To find: Shape of Cross Section when a plane intersect the prism diagonally
A plane intersect the Rectangular prism .i.e, Cuboid diagonally which means plane passes from top edge of cuboid to edge on bottom on opposite side.
Figure is attached.
In this way we get a Rectangular shaped Cross section which includes edges of cuboid and diagonals of the side faces.
Therefore, Rectangle shaped cross section is formed by intersection of plane and prism.