Answer:
$1.84
Step-by-step explanation:
We are given that a letter up to 1 ounce requires postage in the amount of $0.42, and each additional ounce (or fraction of an ounce) has an additional cost.
The function which represents the situation:
Now Joseph has two letters .
The weight of first letter = 2.9 ounces
Cost of first letter =
=
Now , second letter weighs 4.1 ounces
So, cost of second letter =
=
Thus the total amount Josiah can expect to pay for postage = $0.8+$1.04
=$1.84
Hence the total amount Josiah can expect to pay for postage is $1.84
Answer:
$1.84
Step-by-step explanation:
atomic mass
number of neutrons
number of protons
atomic number
• When the ball hits the ground, its height is zero, so you are looking for one of the zeros of the quadratic equation.
• Though you could use several different methods, the easiest way to solve this particular equation is the quadratic formula (provided here). Take the a, b, and c values from the function in the question above.
• When you solve the quadratic for the zeros, you will have two answers. One of the answers will not make sense for a baseball hit into the outfield. The one that does make sense will be the correct answer.
The time that the baseball stays in the air is determined by setting h(t), the height, to 0 and solving for t (time) using the quadratic formula; the positive answer represents the time in seconds that the ball stays in the air.
In order to find how long the baseball will stay in the air, we need to solve for the value of t (time) when the height h(t) is equal to 0. This is given by the formula h(t) = -16t2 + 22t + 3. We equate this to zero and solve for t using the quadratic formula: t = [-b ± sqrt(b2 - 4ac)] / (2a).
Here, a = -16, b = 22, and c = 3. Substituting these values into the formula gives two solutions for t. However, we reject the negative solution since time cannot be negative. Therefore, the positive solution gives the amount of time (rounded to the nearest tenth of a second) the baseball stays in the air before it hits the ground.
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